Discover the G Forces of Braking from 290mph in My Grand Turismo 3 Car

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Discussion Overview

The discussion centers around calculating the G forces experienced by a driver braking from a speed of 290 mph to a complete stop within a time frame of 2.5 seconds. The focus includes both the mathematical approach to determine acceleration and the implications of such forces on safety.

Discussion Character

  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant calculates the G forces to be approximately 11.8 Gs based on an acceleration of -116 m/s².
  • Another participant challenges this calculation, suggesting that the correct acceleration is -51.9 m/s², resulting in about 5.3 Gs.
  • A further conversion into English units is provided, yielding a similar result of 5.3 Gs based on a different method of calculation.
  • Participants express concern for safety, humorously suggesting the necessity of a seat belt given the extreme G forces involved.

Areas of Agreement / Disagreement

There is disagreement regarding the correct calculation of G forces, with multiple competing views presented without resolution.

Contextual Notes

Participants rely on different methods and units for their calculations, leading to varying results. The discussion does not resolve the discrepancies in the calculations presented.

Who May Find This Useful

Individuals interested in physics, automotive engineering, or safety in high-speed scenarios may find this discussion relevant.

Gara
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what kind of G forces does the driver come under when breaking from 290 mph to 0 in 2.5 seconds?
 
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Let's get it in meters per second...
129.642 Meters per second.

Now, our acceleration has to be cahgne in velocity over time. (FinalVelocity-InitialVelocity)/Time...

-116 m/s^2...
We are talking in absolute value...116 m/s^2. Then divide that by 9.81...11.8 G's.

I think that's right.
 
How did you get -116 m/s^2 ? Going from 129.9 m/s to 0 m/s in 2.5 second is (0- 129)/2.5= -51.9 m/s^2. That's 5.3 g.

You can, of course, do it in English units: )(290 mi/hr)/((60 min/hr)(60 sec/min)))*(5280 ft/mi)= 425.33 ft/sec.
Going from 425.33 ft/sec to 0 ft/sec in 2.5 seconds is an acceleration of (0- 425.33)/2.5= -170.33 ft/sec^2.
The acceleration due to gravity (g) is about -32.2 ft/sec^2 so
-170.33 ft/sec^2= -170.33/-32.2= 5.3 g again.
 
hope my guy is using a seat belt! lol
 
Originally posted by Gara
hope my guy is using a seat belt! lol

Hope it's not a 5-point! Unless he already has kids..
 

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