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Natural Numbers - Pi, Log, .... |
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| Nov29-06, 10:29 PM | #1 |
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Natural Numbers - Pi, Log, ....
Greetings,
I'm far from an expert on math and I wanted to appeal to smarter minds to help compile a list of numbers with non-repeating chaotic decimals: Here's the first 2 (the only 2 I can think of) Pi e I'd also include the order of prime numbers because although it can be approximated as to when the next prime will occur, it is still random and (currently) non-deterministic. Can you add some numbers or sequences that fit this mold? Thanks. |
| Nov29-06, 11:02 PM | #2 |
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log is not a number, it's a function. Perhaps you mean 'e.'
The square root of two and three and so on are also irrational numbers. There are, in fact, an infinite number of irrational numbers. - Warren |
| Nov30-06, 08:19 AM | #3 |
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As chroot said, there are an infinite number of irrational numbers and all irrational numbers are "non-repeating" (I don't know what you mean by "chaotic" here) decimals. In fact, in a very specific sense, "almost all" numbers are irrational. And, of course, the set of irrational numbers is uncountable so there cannot exist a "list" of them!
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| Nov30-06, 08:56 AM | #4 |
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Natural Numbers - Pi, Log, ....
There are power-of-the-continuum transcendental numbers (that is, they can be put into one-to-one coreespondence with points on the line). They are defined by not being the root of any algebraic equantion (irrational numbers are just not the root of any linear equations). Because any recursive pattern in the decimal expansion would, I would think, set up an polynomial of which the number would be a root, I don't think there is any finitely generate recursive patter in the decimal expansion of a transcendental number.
e and pi are the two best known transcendental numbers. e was shown to be transendental by Hermite, the same man who is known for Hermitian operators (fun fact: his high school math teacher also taught Galois). Pi was shown to be transcendental by Lindemann in the 1890s. Gel'fond proved the beautiful theorem that if b is any transcendental number and a is any algebraic number (i.e. not transcendental), then ba is transcendental. |
| Nov30-06, 09:34 PM | #5 |
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Thanks guys, very nice answers.
My question was poorly worded, but your answers were great. |
| Dec1-06, 09:29 AM | #6 |
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look into cantor's diagonal argument. it's pretty accesible even to non-experts only rational numbers have repeating decimals. irrationals like sqrt 2 don't repeat. no-one has proved if pi, e, sqrt 2 have evenly distributed digits, equivalent to 'random' (that is are normal numbers), it's just a hypothesis what i love about normal numbers is that if you represent them in base say 30 - using the alphabet, a space, punctuation, to represent the 30 possible digits - then somewhere in the 'digits' must appear any message you'd like. the bible, shakespear, etc. seeing as pi is 'probably' a normal number, somewhere in it's digits is the message "pi is exactly twenty-two over seven, dumbass" monkey, typewriter, infinite time etc. |
| Dec1-06, 09:34 PM | #7 |
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| Dec3-06, 11:48 AM | #8 |
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However, that doesn't mean it's true just because it's irrational. For instance, the first number to be proved transcendental (and all transcendental numbers are irrational) was [tex]\sum_{n=1}^{\infty}10^{-(n!)}[/tex] I can, with 100% certainty, tell you that the digit '2' never appears in that number's decimal expansion, yet it is infinite and non-repeating. It's another one of those 'quirks' of infinitly large sets. For instance {2,3,4,....} is infinitely large but misses out the number 1 (to say nothing of negative numbers, other rationals, irrationals and transcendentals!) yet never repeats a number as you move through the list. |
| Dec3-06, 04:25 PM | #9 |
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