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JK flip flop question.

 
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Dec7-06, 10:15 PM   #1
 

JK flip flop question.

We're analyzing JK flip flop circuits and I don't understand it.

So, Given that J = x, and K = xB' , my notes say that Q+ = JQ' + K'Q. I understand that. Then, substituting, we get xA' + x'A + xB.

I have no idea how that final result was obtained. Can anyone help me with this?
 
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Dec8-06, 12:03 AM   #2
 
Mentor
Show and think about the circuit.
 
Dec8-06, 09:12 AM   #3
 
K = x'B

then what's the complement of K?

K' = ?

And look up the excitation tables.
 
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