Exploring the 21cm Radio Spectral Line of Hydrogen in the Nuclear Magnetic Field

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Homework Help Overview

The discussion revolves around the 21cm radio spectral line of hydrogen, which is linked to the interaction between the magnetic moments of the electron and the nucleus. Participants are exploring the implications of this spectral line and the associated nuclear magnetic field at the electron's average position.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to understand the concept of the average position of the electron and its relation to the nuclear magnetic field. Questions are raised about the meaning of average position and the parameters needed for calculations, such as the gyromagnetic ratio and magnetic moment.

Discussion Status

The discussion is ongoing, with participants expressing confusion about specific terms and calculations. Some have provided references and suggested values, while others are seeking further clarification on the concepts involved.

Contextual Notes

There are indications of uncertainty regarding the definitions of terms like "average position" and the parameters required for calculations, which may affect the participants' understanding of the problem.

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Radio astronomers have found that besides its optical spectral lines,hydrogen exhibits a radio spectral line at a wavelength of 21cm.This spectral line arises from the interaction between magnetic moment of the electron and the magnetic moment of the nucleus.The electron is located within the magnetic field generated by the magnetic moment of the nucleus ,and when electron flips from the spin up to spin down orientation in this magnetic field ,it emits a photon at 21cm wavelength.

What is the value of the nuclear magnetic field at the average poston of the electron?


I don't understand what is meant by average position ,since there is only spin up or down .MAybe i am on wrong track!
 
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They probably mean 0.529 Angstrom, the radius of the first Bohr orbit.
The electron position is described by a wave function that is spread out, but
its average distance is 0.529 Angstrom.
 
I still don't get it

I still dotn get it.

if hc/lambda=g(mi)B

where
g=gyromagnetic number
B=magnetic field

how do i get g and mi ?
 
The 21cm line comes from the hyperfine (spin-spin) splitting. This link shows the full calculation
http://www.pha.jhu.edu/~rt19/hydro/hydro.html"
Formulas are included for the proton magnetic moment and field.
 
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