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The Twin Paradox |
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| Jan14-07, 08:47 PM | #1 |
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The Twin Paradox
Hi all, I am taking a grade 12 physics course and we just covered special relativity theory however one thing troubles me; the twin paradox. The thought experiment proposes that a one twin travels to a distant star and back at a speed approaching that of light while the other twin remains on Earth. The twin on Earth should see his twin in the spaceship age slower, but wouldn't the twin on the ship think the same thing seeing Earth recede at high speed and then return. According to my textbook the answer is NO because the special theory of relativity applies only to inertial frames (in this case the Earth). The situation is not symmetrical since the spaceships velocity must change at the turn around point meaning it is a non-inertial reference frame.
Here is my question; could the twin in the space ship not interpret the event as Earth moving away and then returning, from the frame of reference of the ship does Earth not appear to change its velocity at a turn around point making it non-inertial? Why is this thought experiment not symmetrical? |
| Jan14-07, 09:13 PM | #2 |
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| Jan14-07, 09:16 PM | #3 |
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I was having the same problem, here's a website that explains it pretty well:
http://www.phys.vt.edu/~jhs/faq/twins.html and here's the thread I started where some people expanded some more on what the website explains: http://www.physicsforums.com/showthread.php?t=150894 |
| Jan15-07, 03:49 AM | #4 |
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The Twin Paradox
The twin paradox has been discussed here many times. A forum search on "twin" should turn up plenty of reading material. You might be interested in two detailed descriptions of the same scenario which both show that both twins must agree on what is happening, if they do it correctly:
Using the relativistic Doppler effect to analyze what each twin sees if he watches the other twin through a telescope: http://www.physicsforums.com/showpos...14&postcount=3 Using the Lorentz transformation equations: http://www.physicsforums.com/showpos...08&postcount=3 |
| Jan15-07, 08:56 AM | #5 |
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| Jan15-07, 09:15 AM | #6 |
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IMHO, that "SR applies only to inertial frames" is akin to the inaccurate thinking in kinematics that "velocity is defined as distance over time"... in the sense that a special case or application of a concept is being inappropriately generalized. |
| Jan15-07, 10:07 AM | #7 |
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The twin paradox melts away in GR.
The unaccelerated twin has a world-line between two events with the shape of a geodesic which maximizes the proper time - time measured by the twin's clock. Hence the unaccelerated(earth) twin is a very special observer in spacetime. The earth twin 's clock will run faster than the space twin's clock. There is no symmetry in this case. |
| Jan15-07, 10:15 AM | #8 |
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As an analogy, would you object to a high school textbook on classical mechanics which said "an inertial frame is one where Newton's laws of motion hold", when technically Newton's laws can also be stated in tensor form so that they work in non-inertial frames? |
| Jan15-07, 10:44 AM | #9 |
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often heard misconception that "special relativity can't handle accelerated frames" (which it can!) which is implied by I am advocating more correct statements. Ideally, a statement (a "blurb" or "slogan", if you will) should stand alone. IMHO, it is better to make an incomplete-but-correct statement... rather than one that is incorrect-without-additional-remarks. (An example of a statement that is incorrect-without-additional-remarks is saying "velocity=distance/time" without specifying the restrictive condition when that is true.) In the incomplete-but-correct statement, you have a correct statement without all of the details (which will enlighten you later). In the incorrect-without-additional-remarks statement, you have to have to unlearn an incorrect statement and any other misconceptions derived from it (which will possibly annoy you later). |
| Jan15-07, 12:08 PM | #10 |
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Again, what would you say about the statement, often seen in textbooks, that an inertial frame in classical mechanics can be defined as one where Newton's laws hold? The laws of Newtonian mechanics can be stated in tensor form just like SR, and in this form they hold in accelerated frames too, no? |
| Jan15-07, 12:22 PM | #11 |
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Well, running the risk of getting stuck in the middle of this discussion, strictly speaking acceleration is not handled by SR for the simple reason that acceleration is mitigated by curved space-time.
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| Jan15-07, 12:31 PM | #12 |
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| Jan15-07, 12:33 PM | #13 |
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Are you saying that things simply accelerate by themselves without a need for space-time to curve? That seems to me a clear violation of the equivalence principle. |
| Jan15-07, 12:54 PM | #14 |
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Maybe the textbook could just say "accelerated frames are outside the scope of this textbook"? I think that might make everyone happy.
It seems to me that the definition of "special relativity" is what's basically being argued about. From a purist POV, whatever one can deduce without using the equivalence principle or the Einstein field equations would be considered to be "special relativity". From a pedagogical POV, one wants to separate material that requires advanced mathematics to handle from material that does not require advanced mathematics. Hence, one classifies material that requires tensors or in this case differential geometry to handle as "General Relativity", even though the difference is only the mathematical treatment and not the basic physical assumptions. |
| Jan15-07, 01:01 PM | #15 |
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| Jan15-07, 01:19 PM | #16 |
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I think the main issue consists of the defintion of 'frame'. You don't need to consider the notion of the "frame" of an acclerated observer to calculate hyperbolic motion, so that is not especially problematical.
Some of the trickier technical issues involving frames are really only fully resolved with differential geometry. Unfortunately, this does tend to leave beginning students with strange ideas. The frame-field of an accelreating obserer is really not that much different from the frame of a non-accelerating observer as long as one is sufficiently close to the accelrating observer. Differences only start to creep in as a second order effect of magnitude approximately (1+gL)/c^2. |
| Jan15-07, 01:43 PM | #17 |
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No additional remarks are needed. (Caveat: This does not mean that you can use every equation in SR in accelerated frames. Indeed, not every equation in SR applies in all cases treated by SR. ...Just like: not every equation in Galilean kinematics applies in all cases treated by Galilean kinematics. [e.g. Velocity is not always distance/time.] None of these statements is in conflict with the truth of the statement above.) "SR can't be applied to accelerated frames" is an incorrect statement. You may add remarks to restrict the condition when that statement would be true... for example, "when using equations derived for inertial frames". |
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