## variance

How do I approach finding variance of sample mean of Poisson distribution?
thanks.
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Homework Help
 Quote by EvLer How do I approach finding variance of sample mean of Poisson distribution? thanks.
 I did: Var(X) = E(X2) - (E(X))2 the problem is that this is given for rv X, not X' or X-bar, that's where i get lost. I know that last term is lambda2. Actually what I need to find for this problem is E(X'2), i.e. E(X'2) = Var(X') + lambda2

## variance

ok, last question, pleeeease some one look i can't find much on this anywhere and the book does not say much... i don't have intuition for these things....
can I say that sample variance is sum(lambda)/n?
I found something that said sample variance is Sum(Var[X]) of whatever it is the RV divided by n....
 Recognitions: Homework Help According to my old lecture notes, the sample variance for (X1, ..., Xn) is defined with $$\frac{1}{n} \sum_{i=1}^n(X_{i}-\overline{X})^2$$, where $$\overline{X} = \frac{1}{n}\sum_{i=1}^n X_{i}$$ , and, in your case X~P(lambda).
 Recognitions: Gold Member Science Advisor Staff Emeritus Yes, the Poisson distribution depends on a single parameter and has the property that both mean and standard distribution are equal to that parameter.