Need a bit of help with j-hat and i-hat in a collision

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SUMMARY

The discussion focuses on calculating the velocity of the center of mass for a system of two 3-kg masses with given velocities. The velocities are v(1) = 2 m/s i-hat + 3 m/s j-hat and v(2) = 4 m/s i-hat - 6 m/s j-hat. The formula for the center of mass velocity is correctly identified as v(cm) = (m(1)V(1) + m(2)V(2)) / (m(1) + m(2)). To resolve the vector components, participants suggest treating the i-hat and j-hat components separately before combining them into the final momentum vector.

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jperez94
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Hey there, I'm lost with this one:

Two 3-kg masses have velocities v(1)= 2m/s i-hat plus 3m/s j-hat and v(2)= 4m/s i-hat minus 6m/s j-hat. Find the velocity of the center of mass of the system.


Now, I know how to go about calculating the velocity of the center of mass (v(cm)= m(1)V(1)+m(2)V(2)/m(1)+m(2)

The thing that throws me off is the j-hats and i-hats. How do I come out with a vector number? I thought of the pothagarem(sp?) therom, but decided that couldn't work. Any ideas? Thanks.
 
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u mean pythagoras Theorem , it should work
 
Treat "i-hat" and "j-hat" as two separate problems. Then put them back together into the "momentum vector" with i and j components.
 

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