Voltage potential due to 2 charges

Click For Summary
To find the electric potential at points a and b due to charges Q1 = +1.60 nC and Q2 = -1.60 nC, the equation V = kQ/r is used. The user initially calculated the potential but received an incorrect result of 191700 V. A participant pointed out that the user mistakenly used microcoulombs instead of nanocoulombs in their calculations. Correcting this numerical error is essential for obtaining the right potential values. The discussion emphasizes the importance of unit accuracy in physics problems.
bobby3280
Messages
11
Reaction score
0

Homework Statement


Find the potential at points a and b in the diagram for charges Q1 = +1.60 nC and Q2 = -1.60 nC.

I know b is 0
physics.gif



Homework Equations



V = kQ/r

The Attempt at a Solution



I tried this using the equation and got

8.99e9 * [( +1.60e-6 / .05) + ( -1.60e-6 / .15 ) ] = 191700 V but this isn't right any suggestions??
 
Physics news on Phys.org
bobby3280 said:

Homework Statement


Find the potential at points a and b in the diagram for charges Q1 = +1.60 nC and Q2 = -1.60 nC.

I know b is 0
physics.gif



Homework Equations



V = kQ/r

The Attempt at a Solution



I tried this using the equation and got

8.99e9 * [( +1.60e-6 / .05) + ( -1.60e-6 / .15 ) ] = 191700 V but this isn't right any suggestions??

If its nancoulombs as the question suggests then you've just made a numerical error in the solution. Nano = x10-9
 
Wow how'd I miss that thanks!
 

Similar threads

Replies
2
Views
1K
Replies
13
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
8
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
8K