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Signal Analysis - Invertibility |
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| Feb7-07, 01:51 AM | #1 |
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Signal Analysis - Invertibility
I don't understand why my book is saying that this system is not invertible.
y(t) = cos(x(t)) ? Wouldn't, arccos{ y(t) } = x(t) and therefore be an inverse system? |
| Feb7-07, 04:20 AM | #2 |
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First check on what your book says the definition of invertible is.
What about times T1 and T2, where T1 and T2 are different x(T1) = 0, x(T2)= 2PI y(T1) = 1 and y(T2)=1 Suppose y(t)=1 what is the value of t? |
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