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Signal Analysis  Invertibility 
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#1
Feb707, 01:51 AM

P: 837

I don't understand why my book is saying that this system is not invertible.
y(t) = cos(x(t)) ? Wouldn't, arccos{ y(t) } = x(t) and therefore be an inverse system? 


#2
Feb707, 04:20 AM

P: 123

First check on what your book says the definition of invertible is.
What about times T1 and T2, where T1 and T2 are different x(T1) = 0, x(T2)= 2PI y(T1) = 1 and y(T2)=1 Suppose y(t)=1 what is the value of t? 


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