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Work and Charge |
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| Feb7-07, 12:50 PM | #1 |
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Work and Charge
1. The problem statement, all variables and given/known data
A charge of 2.0 microC is located in a uniform electric field of intensity 4.0*10^5 N/C. How much work is required to move this charge 20 cm along a path making an angle of 60° with the electric field? a.0.14 J b.0.34 J c.80 mJ d.14 J e.8.0 J 2. Relevant equations See below. 3. The attempt at a solution W = E*q*d*cos theta = (4.0*10^5 N/C)*(2.0*10^-6 C)*(0.2 m) *cos(60) = 0.08 J I just wanted to know if the angle and formula that I used are correct. Thanks. |
| Feb7-07, 01:06 PM | #2 |
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Yes, it's correct.
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