|Feb7-07, 12:50 PM||#1|
Work and Charge
1. The problem statement, all variables and given/known data
A charge of 2.0 microC is located in a uniform electric field of intensity 4.0*10^5 N/C. How much work is required to move this charge 20 cm along a path making an angle of 60° with the electric field?
2. Relevant equations
3. The attempt at a solution
W = E*q*d*cos theta = (4.0*10^5 N/C)*(2.0*10^-6 C)*(0.2 m) *cos(60) = 0.08 J
I just wanted to know if the angle and formula that I used are correct.
|Feb7-07, 01:06 PM||#2|
Yes, it's correct.
|Similar Threads for: Work and Charge|
|How much work must be done to carry a +2.3 X 10^-3 C charge from 65 cm to 15 cm?||Introductory Physics Homework||12|
|Work done to move a charge||Introductory Physics Homework||12|
|The work required for adding a charge to an infinite charge distribution||Advanced Physics Homework||1|
|Work on done on a test charge||Introductory Physics Homework||2|
|work per charge||Advanced Physics Homework||8|