Cauchy-Riemann conditions

ultimateguy

1. The problem statement, all variables and given/known data
The functions u(x,y) and v(x,y) are the real and imaginary parts, respectively, of an analytic function w(z).
Assuming that the required derivatives exist, show that

[tex]\bigtriangledown^2 u=\bigtriangledown^2 v=0[/tex]

Solutions of Laplace's equation such as u(x,y) and v(x,y) are called harmonic functions.


2. Relevant equations
Cauchy-Riemann conditions:

[tex]\frac{\delta u}{\delta x} = \frac{\delta v}{\delta y}[/tex]
[tex]\frac{\delta u}{\delta y} = -\frac{\delta v}{\delta x}[/tex]


3. The attempt at a solution
I expanded [tex]\bigtriangledown^2 u = \frac{\delta u}{\delta x}\frac{\delta u}{\delta x} + \frac{\delta u}{\delta y}\frac{\delta u}{\delta y}[/tex] and using the Cauchy-Riemann conditions I found

[tex]\bigtriangledown^2 u = \frac{\delta v}{\delta y}\frac{\delta v}{\delta y} + \frac{\delta v}{\delta x}\frac{\delta v}{\delta x}=\bigtriangledown^2 v[/tex]

What I can't figure out how to do is prove that this is equal to zero.

Meir Achuz

Your eqs. for del^2 are wrong.
[tex]\nabla^2 u=\partial_x\partial_x u+\partial_y\partial_y u.[/tex]

ultimateguy

Dang, you're right. Can I dot it into an element of length like this?

[tex]\bigtriangledown^2 u \bullet d\vec{r}^2 = \frac{\delta}{\delta x}\frac{\delta u}{\delta x} dx^2 + \frac{\delta}{\delta y}\frac{\delta u}{\delta y} dy^2[/tex]

ultimateguy

There is a hint in the problem that says I need to construct vectors normal to the curves [tex]u(x,y)=c_i[/tex] and [tex]v(x,y)=c_j[/tex]. Wow, I'm pretty lost.

HallsofIvy

The Cauchy-Riemann equations are
[tex]\frac{\partial u}{\partial x}= \frac{\partial v}{\partial y}[/tex]
[tex]\frac{\partial u}{\partial y}=-\frac{\partial v}{\partial x}[/tex]
which is what you have, allowing for your peculiar use of [itex]\delta[/itex] rather than [itex]\partial[/itex]!

Now just do the obvious: differentiate both sides of the first equation with respect to x and differentiate both sides of the second equation with respect to y and compare them.

Are you sure that the hint is for this particular problem? A normal vector to u(x,y)= c is
[tex]\frac{\partial u}{\partial x}\vec{i}+ \frac{\partial u}{\partial y}\vec{j}[/tex]
and a normal vector to v(x,y)= c is
[tex]\frac{\partial v}{\partial x}\vec{i}+ \frac{\partial v}{\partial y}\vec{j}[/tex].
Using the Cauchy-Riemann equations, that second equation is
[tex]-\frac{\partial u}{\partial y}\vec{i}+ \frac{\partial u}{\partial x}\vec{j}[/tex]
which tells us the the two families of curves are orthogonal but that does not directly tell us about [itex]\nabla^2 u[/itex] and [itex]\nabla^2 v[/itex].

ultimateguy

Thanks for your reply.

There is a part b) to the problem, and it is this:

b) Show that

[tex]\frac{\partial u}{\partial x}\frac{\partial u}{\partial y} + \frac{\partial v}{\partial x}\frac{\partial v}{\partial y} = 0[/tex]

I solved it easily using the Cauchy-Riemann equations, so I figured that the hint was for the first part.