# Maxwell's speed distribution law

by Kolahal Bhattacharya
Tags: distribution, maxwell, speed
 PF Gold P: 4,087 Maxwell's speed distribution law I think the argument holds because $$V^2 = V_x^2 + V_y^2 + V_z^2$$ therefore $$P(V^2) = P( V_x^2 + V_y^2 + V_z^2 )$$ and the next step follows from the independence of V_x, V_y and V_z.