
#1
Mar1107, 05:26 PM

P: 70

Whilst trying to refresh myself on what a dual space of a vector space is I have confused myself slightly regarding conventions. (I am only bothered about finite dimensional vector spaces.)
I know what a vector space, a dual space and a basis of a vector space are but dual bases: I seem to recall something about the delta function being used. Does every basis have a dual basis or just standard the bases (i.e. (1,0,..,0), (0,1,0,...,0) , ... (0, ... ,0,1) )? Does the delta function rule have to apply to a dual basis or is it just a condition which ensures that a dual basis of an orthonormal basis is also orthonormal? 



#2
Mar1107, 05:35 PM

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Given a basis e_i of a vector space V, the dual basis of V* is defined by f_i that satsify the rule f_i(e_j)=delta_{ij}. As the definition indicates, every basis V goves rise to a dual basis of V*.
Orthonormality doesn't enter into the question (these are just vector spaces, not inner product spaces). 



#3
Mar1107, 06:04 PM

P: 70

Ah, so the delta function ensures a 11 correspondance beteween the two sets of bases. Thanks.




#4
Mar1507, 09:28 AM

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Dual Basis
the infinite dimensional case is more interesting. I.e. the functions dual to a basis of V do not then give absis for V*. I.e. a linear combination of those dual functions must vanish on all but a finite number of the original basis vectors, but a general linear functiion can do anything on them.
so how do you find a natural basis for ALL linear functions? I do not know the answer. perhaps there is no nice basis. e.g. as an analogy think of a linear function on the positive integers with values in the set {0,...,9} as an infinte decimal. then how would you find a "basis" for all infinite decimals, such that every other infinite decimal is a finite Z linear combination of those? this is not a perfect analogy but gives some idea. i.e. a big problem is the basis would have to be uncountable. 



#5
Mar1507, 01:33 PM

Math
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Thanks
PF Gold
P: 38,886

The dual of an infinite dimensional vector space is not, in general, isomorphic to the original space (but the dual of the dual is!).




#6
Mar1507, 04:57 PM

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