Register to reply

Translational Speed

by Kelschul
Tags: speed, translational
Share this thread:
Kelschul
#1
Mar12-07, 09:44 PM
P: 5
A bowling ball encounters a 0.760-m vertical rise on the way back to the ball rack, as the drawing illustrates. Ignore frictional losses and assume that the mass of the ball is distributed uniformly. The translational speed of the ball is 7.88 m/s at the bottom of the rise. Find the translational speed at the top.
Phys.Org News Partner Science news on Phys.org
Apple to unveil 'iWatch' on September 9
NASA deep-space rocket, SLS, to launch in 2018
Study examines 13,000-year-old nanodiamonds from multiple locations across three continents
Kurdt
#2
Mar13-07, 07:11 AM
Emeritus
Sci Advisor
PF Gold
P: 4,980
You really need to show some working before you can receive any help. As a hint you can think about the conservation of energy.
despanie
#3
May5-07, 03:12 PM
P: 4
Quote Quote by Kelschul View Post
A bowling ball encounters a 0.760-m vertical rise on the way back to the ball rack, as the drawing illustrates. Ignore frictional losses and assume that the mass of the ball is distributed uniformly. The translational speed of the ball is 7.88 m/s at the bottom of the rise. Find the translational speed at the top.
HOW IS THE EQUATION SETUP FOR THIS PROBLEM

despanie
#4
May5-07, 03:23 PM
P: 4
Angry Translational Speed

Quote Quote by Kelschul View Post
A bowling ball encounters a 0.760-m vertical rise on the way back to the ball rack, as the drawing illustrates. Ignore frictional losses and assume that the mass of the ball is distributed uniformly. The translational speed of the ball is 7.88 m/s at the bottom of the rise. Find the translational speed at the top.
kE1+PE1=KE2+PE2
1/2(MKG)(7.880)^2+(MKG)(9.8)(.76M)=1/2MKG(V)^2+MKG(9.8)(X)
despanie
#5
May5-07, 03:25 PM
P: 4
Quote Quote by despanie View Post
kE1+PE1=KE2+PE2
1/2(MKG)(7.880)^2+(MKG)(9.8)(.76M)=1/2MKG(V)^2+MKG(9.8)(X)
WILL THIS EUATION WORK FOR THE SPEED
hage567
#6
May5-07, 03:33 PM
HW Helper
P: 1,539
You're on the right track, but you mixed up your gravitational potential energy terms a bit. If you take the bottom of the rise as your reference point, what is the gravitational potential energy of the ball before it goes up the rise?


Register to reply

Related Discussions
Translational speed Introductory Physics Homework 0
Confused translational speed Introductory Physics Homework 10
Translational Equilibrium Engineering, Comp Sci, & Technology Homework 4
Translational speed help! Introductory Physics Homework 1
Change in Translational KE of a gas Classical Physics 3