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Questions on electrochemical cells using Zn, Cu

 
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Apr18-07, 11:38 AM   #1
 

Questions on electrochemical cells using Zn, Cu


The problem

http://www.chem.iastate.edu/group/Gr.../CuZncell.html

After veiwing the animation found at the website above answer these questions:

Is there an electron transfer between species?

Which species is losing electrons

Which species is gaining electrons?

Write down the oxidation half reaction under the species that is undergoing oxidation.

Write down the reduction half reaction under the species that is undergoing reduction.

What is the Anode?

What is the Cathode?

Which direction is the spontaneous reaction? Explain your reasoning.

Write the complete balanced equation for the reaction.


2.The attempt at a solution

Is there an electron transfer between species? Yes

Which species is losing electrons? Zinc/Zn

Which species is gaining electrons? Copper/Cu

Write down the oxidation half reaction under the species that is undergoing oxidation. Zn-> Zn 2+

Write down the reduction half reaction under the species that is undergoing reduction. Cu 2+ ->Cu

What is the Anode? Zinc/Zn

What is the Cathode? Copper/Cu

Which direction is the spontaneous reaction? Explain your reasoning.

The spontaneous reaction is occuring from the zinc to the copper because the zinc is losing electrons and the copper is gaining electrons.

Write the complete balanced equation for the reaction.

Zn 2+ + Cu --> Cu 2+ +Zn



Please help me here!!

I need someone to check my answers, I'm pretty sure about the first ones, but the last one about the balanced equation I think it wrong.


Any help would be greatly appreciated.


THANKS!!
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Apr18-07, 04:11 PM   #2
 
PLEASE please PLEASE HELP!!!
Apr18-07, 04:51 PM   #3

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If copper is the species being reduced, how can your reaction be correct?

Zn 2+ + Cu --> Cu 2+ +Zn ??????
Apr24-07, 08:51 AM   #4
 

Questions on electrochemical cells using Zn, Cu


Thats exactly why I need help ! !!
Apr24-07, 09:13 AM   #5

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You will notice that the metallic zinc electrode is being converted to Zn+2 and that the Cu+2 ions in solution are picking up electrons and depositing on the surface of the copper electrode. Write down these two processes one after the other:

A+2 + 2e- ------> A
B -------> B+2 + 2e-
______________________

Add them together and see what you get...
Apr25-07, 09:21 AM   #6
 
A+2 + B ---> B+2 + A

we don't factor in the 2e- because they cancel each other out right?

so it would be:

Zn+2 +2e- ----> Zn
Cu----> Cu+2 + 2e-
___________________
Zn+2 + Cu----> Cu+2 + Zn


Right?
Apr25-07, 09:23 AM   #7
 
wait thats what I had before...

oh god.

would it be

Cu+2 +Zn ----> Cu + Zn+2 ?
Apr25-07, 11:08 AM   #8

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That's correct. Now examine each of the metals in the equation. Which one is being oxidized and which is being reduced?
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