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SR clarification needed |
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| Mar22-04, 11:08 PM | #1 |
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SR clarification needed
In The Elegant Universe, Briane Greene states that, "Einstein proclaimed that all objects in the universe are always traveling through spacetime at one fixed speed - that of light." If something is sitting still, then all the object's "motion" is in the time dimension. Can someone demonstrate how this claim works out mathematically?
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| Mar22-04, 11:41 PM | #2 |
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The "distance" (it takes on a subtely different meaning for SR, i.e. it is spacetime distance) formula for SR is
[tex]ds^2 = dx^2 + dy^2 + dz^2 + (icdt)^2[/tex] If you fix the s and let the x, y, and z terms be insigificant, the time term is dominant. On the other hand, if the x, y, and/or z terms are significant, then the time term must be less significant. cookiemonster |
| Mar23-04, 01:35 AM | #3 |
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I think Brian Greene explains it mathematically at the end of the book, in one of his 'footnotes'!
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| Mar23-04, 10:17 AM | #4 |
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SR clarification needed[tex](\sigma _{0}dc\tau)^2 = (\sigma _{0}dct)^2 + (\sigma _{x}dx)^2 + (\sigma _{y}dy)^2 + (\sigma _{z}dz)^2[/tex]. The Pauli matrices serve as a description of an orthonormal basis with the 2x2 identity associated with time. Boosts between frames are then described as rotatons in spacetime and this spacetime structure revealing spin half eigenvectors corresponding to rotations in space is then understood as the source of such quantum mechanical phenomenon. The ict concept is as outdated and uninstructive as the "relativistic mass" missnomer. |
| Mar23-04, 10:42 AM | #5 |
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[tex]|U| = [g_{\mu}_{\nu}U^{\mu}U^{\nu}]^{\frac{1}{2}} = c[/tex]. In the correct relativistic description which he is using everything always travels at this speed c in that way following geodesics when unacted on by real forces and all that real forces do is deflect them from geodesic motion. The real forces just rotate their direction in spacetime. |
| Mar23-04, 12:00 PM | #6 |
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Greene is not refering to a spatial displacement dr and he's not refering to a time interval dt. He's refering to a spacetime displacement ds and a proper time interval dT. But moving through spacetime with speed "c" Greene means that if U is the particle's 4-velocity. Defined as follows Let dX be a space time displacement defined as dX = (ct, dx, dy, dz) Then the particle's 4-velocity U is defined as U = dX/dT Then it follows that U*U = c2 or U*U = -c2 depending on the choice of metric you choose. However if the particle is a photon then this relation is meaningless as is the 4-velocity as it is defined above. So don't get the idea that a photon's speed through spacetime is c. It's highly unintuitive to say the all objects move through spacetime at speed c since the term "motion" brings to mind spatial movement. Even a body at rest has a non-zero value of ds. And when it comes to the speed of light then you can't even assign a speed to it in the sense that Greene is speaking. |
| Mar23-04, 05:29 PM | #7 |
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Thanks for the info! I think the problem with the quote does lie in the use of language -- the concepts of "traveling" and "motion" are colloquially associated with spatial displacement vs. time.
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| Mar25-04, 09:48 PM | #8 |
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Recognitions:
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I would just make one minor adjustment from "time dimension" to "time direction." |
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