
#1
May307, 06:24 PM


#2
May307, 06:41 PM

Mentor
P: 40,877

Looks like you've not been given enough information to solve the problem.




#3
May307, 07:14 PM

P: 1,583





#4
May307, 07:17 PM

Sci Advisor
HW Helper
P: 2,886

Seemingly Simple Statics Problem 



#5
May307, 07:31 PM

P: 34

you have 1 equation relating T1 T2 AND T3
you have a second equation relating T2 to T3, so you can substitute into the first for only 2 unknowns. Now you can get torque around another point to relate T1 to T3, or T1 to T2, and you should be all set. I recommend getting the torque around the center of mass, then substituting T3 with T2 for this and the first equation. Then you will have 2 equations and 2 unknowns and it's easy. 



#6
May307, 07:34 PM

Mentor
P: 40,877





#7
May307, 09:02 PM

P: 1,583





#8
May307, 09:10 PM

P: 1,583





#9
May407, 10:00 AM

Sci Advisor
HW Helper
P: 2,886

It's indeed obvious that there is no unique solution, As Doc Al said. There is a solution with only two strings. Therefore, there is an infinite number of solutions with a third string. For example, the possible values of T_1 range from a minimum value of 0 (in which case [itex] T_3=Mg \frac{L/2x}{Lx}} [/itex] and [itex] T_2=\frac{MgL}{2(Lx)}[/itex]up to a maximum value of Mg/2 (in which case [itex]T_2 =0, T_3 = Mg/2[/itex]). 


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