Identifying Particles by Mass: A High-Energy Physics Experiment

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SUMMARY

This discussion centers on identifying a subnuclear particle in a high-energy physics experiment using its mass derived from kinetic energy and motion in a magnetic field. The experiment involves a particle with a radius of 0.27 meters, a magnetic field strength of 2.7 x 10^-2 T, and a kinetic energy of 4.1 x 10^-16 J. Through calculations involving the equations KE = mv²/2 and r = mv/qB, the mass was determined to be 1.49 x 10^-9 kg, confirming the particle as a proton. The discussion emphasizes the importance of not skipping steps in calculations to avoid errors.

PREREQUISITES
  • Understanding of kinetic energy equations in physics
  • Familiarity with the motion of charged particles in magnetic fields
  • Knowledge of basic particle physics, including mass values of electrons, pions, and protons
  • Ability to manipulate algebraic equations for solving physics problems
NEXT STEPS
  • Study the Lorentz force and its application in particle motion
  • Learn about the relationship between kinetic energy and mass in high-energy physics
  • Explore advanced topics in particle identification techniques
  • Review the principles of magnetic confinement in particle accelerators
USEFUL FOR

Physicists, students in high-energy physics, and anyone interested in particle identification and the principles of motion in magnetic fields will benefit from this discussion.

tandoorichicken
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why u should not skip steps

In a high-energy physics experiment, a subnuclear particle moves in a circular arc of 0.27-m radius perpendicular to a magnetic field of 2.7*10^-2 T. The kinetic energy of the particle is determined to be 4.1*10^16 J. Identify the particle from its mass. The masses of the electron, pion, and proton are 9.1*10^-31 kg, 2.5*10^-28 kg, and 1.67*10^-27 kg, respectively. Assume that the particle is known to have a positive charge equal to the magnitude of the electron charge.

Okay, so I know r= 0.27, B= 2.7*10^-2, q= 1.6*10^-19 C, and KE= 4.1*10^-16 J. Now I need to find mass to id the particle.
[tex]KE = \frac{mv^2}{2}[/tex], so [tex]v = \sqrt{2m * (KE)}[/tex].
[tex]r = \frac{mv}{qB}[/tex], and then I subbed in the v from the kinetic energy equation.
[tex]r = \frac{m\sqrt{2m * (KE)}}{qB}[/tex]
[tex]\frac{rqB}{\sqrt{2KE}} = m^{3/2}[/tex]
m = 1.49*10^-9.

I really screwed this up didnt I? Was it a conceptual or a math error?
 
Last edited:
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Crap.

So it was a dumb math error. Perfect example of why you shouldn't skip steps like I do.

[tex]KE = \frac{mv^2}{2} \rightarrow 2KE = mv^2 \rightarrow \frac{2KE}{m} = v^2 \rightarrow v = \sqrt{\frac{2KE}{m}}[/tex].

Remember guys, show all your work!
hehe,
Tchicken.
 
By the way, the particle is a proton.
 

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