How Much Force Is Needed to Move an Object Up an Inclined Plane?

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SUMMARY

The discussion focuses on calculating the force required to move a 16 kg object up a frictionless inclined plane at a 60-degree angle with a uniform acceleration of 2.0 m/s². The net force necessary is derived from the equation F = mg sin(θ) + ma, where m is the mass, g is the gravitational acceleration (9.8 m/s²), and θ is the angle of inclination. The participant confirms that the gravitational force component acting down the plane must be overcome in addition to providing the required acceleration.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Basic trigonometry, specifically sine and cosine functions
  • Knowledge of gravitational force calculations
  • Familiarity with inclined plane physics
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  • Study the derivation of forces on inclined planes in physics
  • Learn about the applications of Newton's laws in real-world scenarios
  • Explore frictionless motion and its implications in physics
  • Investigate the effects of different angles on force calculations
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Physics students, educators, and anyone interested in mechanics, particularly those studying forces on inclined planes and motion dynamics.

nutzweb
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hey guys! i need some help, a big help. this is urgent... can somebodyhelp me solve this problem:

what force, applied parallel to the plane, is necessary to move a 16 kg object up africtionless palne with a uniform acceleration of 2.0 m/s2 if the plane makes an angle of 60 degrees with the horizontal?

pls somebody help me. i really need it badly. hope somebody would reply today. thanks...
 
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Is the plane on the surface of earth, so that the body is subject to a gravitational force of (16 kg)*(9.8 m/s^2)?

Is the acceleration wrt the plane or the ground? Makes a big difference.

I assume the answers are yes and wrt the plane.

The NET force necessary to move the body 2 m/s^2 is simply mass * acceleration = (16 kg)*(2 m/s^2).

However, you need more than that to overcome the gravitational force. The body is kept from moving straight down by the plane, so it would only go down the plane with a force of (16 kg)*(9.8 m/s^2)cos 30 degrees. Reverse that force and add to the above ("NET").

Now, I may have made a mistake somewhere, so go over that solution carefully. Don't blame me, it was a rush job, right, boss? :smile:
 
nutzweb said:
what force, applied parallel to the plane, is necessary to move a 16 kg object up africtionless palne with a uniform acceleration of 2.0 m/s2 if the plane makes an angle of 60 degrees with the horizontal?
The component of the object's weight parallel to the plane is [itex]mg\sin\theta[/itex] acting down the plane. The applied force F (acting up the plane) must be enough to overcome that and produce the needed acceleration:
[tex]F = mg\sin\theta + ma[/tex]
 

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