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how to lift water out of a pool... |
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| Jun5-07, 08:38 PM | #1 |
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how to lift water out of a pool...
1. The problem statement, all variables and given/known data
given, diameter and height of pool, depth of water, density of water and gravitational acceleration. g = 9.8 height is 4m 2r = 20m depth of water = 3.5m density =1000kg/m^3 So, I'm supposed to find how much work is needed in joules to lift the water out of the pool. 2. Relevant equations could I use density times gravity times volume to get my force? is my distance for my water to travel 4.5m? 3. The attempt at a solution Anyways, I've tried to use my volume for the pool and the volume I have of water * density *gravity to come up with my force and then used 4.5m as my distance to come up with my work needed to lift water out of a pool. I ended up with 1.08E7 joules but that's incorrect so any help would be appreciated. BTW, this is a cal 2 problem/integration problem |
| Jun5-07, 08:41 PM | #2 |
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if it is a cal2/integration problem why aren't you doing any integration? do you know the formula for work?
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| Jun5-07, 08:48 PM | #3 |
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Use the volume of the water and the density to get mass. It would appear that the pool is a right circular cyliner.
Rasining a mass m some distance h in a gravity field producing a local acceleration g increases the potential energy by mgh. |
| Jun5-07, 08:53 PM | #4 |
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how to lift water out of a pool...
I've tried integrating it and I've tried astronuc's advice with no success, any ideas?
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| Jun5-07, 09:03 PM | #5 |
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I'm retarded, integration works. Alright, so with a mixture of the advice, correct answer is 2474002 joules. Thanks again fellas.
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| Jun5-07, 09:05 PM | #6 |
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weight density = 9800 N/m^3
work = integral {0 to 3.5} (9800)(pi*10^2)(4 - y)dy work = 2.4 * 10^7 Joules |
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