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how to lift water out of a pool...

 
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Jun5-07, 08:38 PM   #1
 

how to lift water out of a pool...


1. The problem statement, all variables and given/known data
given, diameter and height of pool, depth of water, density of water and gravitational acceleration.
g = 9.8
height is 4m
2r = 20m
depth of water = 3.5m
density =1000kg/m^3
So, I'm supposed to find how much work is needed in joules to lift the water out of the pool.

2. Relevant equations
could I use density times gravity times volume to get my force?
is my distance for my water to travel 4.5m?


3. The attempt at a solution
Anyways, I've tried to use my volume for the pool and the volume I have of water * density *gravity to come up with my force and then used 4.5m as my distance to come up with my work needed to lift water out of a pool. I ended up with 1.08E7 joules but that's incorrect so any help would be appreciated.

BTW, this is a cal 2 problem/integration problem
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Jun5-07, 08:41 PM   #2
 
if it is a cal2/integration problem why aren't you doing any integration? do you know the formula for work?
Jun5-07, 08:48 PM   #3
 
Admin
Use the volume of the water and the density to get mass. It would appear that the pool is a right circular cyliner.

Rasining a mass m some distance h in a gravity field producing a local acceleration g increases the potential energy by mgh.
could I use density times gravity times volume to get my force?
Yes

is my distance for my water to travel 4.5m?
Well that depends, if one is lifting the CM of the pool water 4 m or (4 m + 1.75 m) or 5.75 m, which is 4 m from the top of the pool.
Jun5-07, 08:53 PM   #4
 

how to lift water out of a pool...


I've tried integrating it and I've tried astronuc's advice with no success, any ideas?
Jun5-07, 09:03 PM   #5
 
I'm retarded, integration works. Alright, so with a mixture of the advice, correct answer is 2474002 joules. Thanks again fellas.
Jun5-07, 09:05 PM   #6
 
weight density = 9800 N/m^3

work = integral {0 to 3.5} (9800)(pi*10^2)(4 - y)dy

work = 2.4 * 10^7 Joules
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