Current from 2.2 Micro F Capacitor

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SUMMARY

The maximum current delivered by a 2.2 Micro F capacitor connected to a North American outlet (Vrms = 110V, f = 60 Hz) is calculated using the formula I = Vmax / XC. The correct capacitive reactance (XC) is determined to be 1.2 kΩ, leading to a maximum current (Imax) of 91.2 mA. The initial calculation of XC as 8.29 ohms was incorrect, highlighting the importance of accurate calculations in electrical engineering.

PREREQUISITES
  • Understanding of capacitive reactance (XC)
  • Familiarity with AC voltage and frequency (Vrms and f)
  • Basic knowledge of Ohm's Law
  • Ability to perform calculations involving complex numbers in electrical engineering
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  • Study the principles of capacitive reactance in AC circuits
  • Learn about the relationship between voltage, current, and impedance in AC systems
  • Explore the effects of frequency on capacitive reactance
  • Review practical applications of capacitors in power supply circuits
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Electrical engineers, students studying circuit theory, and anyone involved in designing or analyzing AC circuits will benefit from this discussion.

cseet
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Hi all,
can somebody please advise whether the below answer is correct... or am I on the right path??

Q: What maximum current is delivered by a 2.2 Micro F capacitor when connected to a North American Outlet where Vrms = 110V and f = 60 hz?

my answer:
I = Vmax / XC

XC = 1 / wC
= 1 / 2 pie 60 * (2.2 * 10E-6)
= 8.29 ohm

I = Vmax / XC
= 110 / 8.29
= 13.29 A

Please kindly correct me if I was wrong...
thanks
Cseet
 
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You are correct, except for the calculation of Xc. The formula is correct, but you miscalculated it. Xc should be 1.2kohm, and Imax should be 91.2mA.
 
Hi Chen,
thanks a lot, you're a GEM!
cseet
 

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