- #1
ReidMerrill
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- 2
Homework Statement
A capacitor has a peak current of 240 μA when the peak voltage at 250 kHz is 2.7 V .
Part A
What is the capacitance?
Part B
If the peak voltage is held constant, what is the peak current at 500 kHz
Homework Equations
Xc=1/wC
Vc=IcXc
The Attempt at a Solution
I rearranged equation 2 to solve for Xc = 2.7V/0.000240A = 11250
I then rearranged equation to to solve for C =1/wXc = 3.56x10-4
This is not correct. Why is this not correct and what is the proper way to go about solving it?
Thank you.
Correction: I re-did the second calculation and got 3.56x10-10F by properly converting kHz to Hz but it's still wrong.
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