|Jun18-07, 01:01 AM||#1|
Electric potential, potential difference, and potential energy
1. Here is a problem that I know how to solve
Through what potential difference would an electron need to be accelerated for it to achieve a speed of 2.3% of the speed of light (2.99792x10^8 m/s), starting from rest? Answer in units of V.
For this problem I used:
deltaK + deltaU = 0 (1/2)mv^2 - 0 = -qdeltaV
2. Now here is a similar problem that I can't seem to solve
An electron moving parallel to the x axis has an initial speed of 2x10^6 m/s at the origin. Its speed is reduced to 500000 m/s at the point p, 1cm away from the origin. The mass of the electron is 9.10939x10^-31 kg and the charge of the electron is -1.60218x10^-19 C. Calculate the magnitude of the potential difference between this point and the origin. Answer in units of V.
I tried to use the same approach for this problem:
(1/2)m2v2^2 - (1/2)m1v1^2 = -qdeltaV
(1/2)m(v2^2 - v1^2) / -q = deltaV (1/2)(9.10939x10^-31)(500000^2 - (2x10^6)^2) / 1.60218x10^-19 = deltaV -10.66054142V = deltaV
3. Here is something else that I can't seem to solve
Calculate the speed of a proton that is accelerated from rest through a potential difference of 69V. Answer in units of m/s.
I attempt to use the same formula:
(1/2)mv^2 - 0 = -qdeltaV (1/2)(1.67262158x10^-27)v^2 = (-1.60218x10^-19)(69)
Any hint as to what concepts I'm missing here would be greatly appreciated. :)
|Jun18-07, 07:01 PM||#2|
I figured it out.
|Jun18-07, 07:09 PM||#3|
how do u do it?
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