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Why adj( U(t)) * U(t) = I where U(t) is a propagator in QM? |
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| Jul19-07, 11:24 PM | #1 |
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Why adj( U(t)) * U(t) = I where U(t) is a propagator in QM?
This is probably really obvious but can someone explain to me why adjiont( U(t)) * U(t) = I where U(t) is a propagator in QM and I is the identity.
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| Jul20-07, 12:31 AM | #2 |
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Isn't that basically the definition of U?
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| Jul20-07, 01:17 AM | #3 |
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Look at what happens if you time-reverse the Schrödinger equation.
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| Jul20-07, 02:12 AM | #4 |
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Why adj( U(t)) * U(t) = I where U(t) is a propagator in QM?Eugene. |
| Jul20-07, 05:29 PM | #5 |
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in the language of operator theory, i believe another proof is via Stone's theorem.
it is always a bit startling to realize that many of the properties of QM follow very naturally from the mathematical properties of the Hilbert space. for example, many people are (for some reason) surprised when i tell them that the resolution of the identity, or complete set of states, [tex]\sum_i |i><i| = 1[/tex] is merely a trivial result of vector calculus, e.g. [tex]\vec{v} = \sum_i \vec{e_i} (\vec{e_i} \cdot \vec{v}) [/tex] with an arbitrary basis |
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