Register to reply

Fourier Coefficients

by dimensionless
Tags: coefficients, fourier
Share this thread:
Aug1-07, 09:52 AM
P: 464
A function [tex]f(t)[/tex] can be represented by the expansion

f(t) = \frac{1}{2}A_{0} + A_{1}cos(\omega t) + A_{2}cos(2 \omega t) + A_{3}cos(3 \omega t) + ....
B_{1}sin(\omega t) + B_{2}sin(2 \omega t) + B_{3}sin(3 \omega t) + ....

Do the constants [tex]A_{n}[/tex] and [tex]B_{n}[/tex] the same thing as the real and imaginary components of the Fourier transform? If so, why is there no imaginary component in the zeroth term?
Phys.Org News Partner Science news on
'Smart material' chin strap harvests energy from chewing
King Richard III died painfully on battlefield
Capturing ancient Maya sites from both a rat's and a 'bat's eye view'
Aug1-07, 04:26 PM
Sci Advisor
P: 6,106
In computing the Fourier transform, the kernel is of the form einwt. For A0, the kernel is simply 1, so there is no imaginary part.

Register to reply

Related Discussions
Partial sum of Fourier Coefficients Calculus & Beyond Homework 8
Fourier Coefficients Differential Equations 3
Fourier coefficients Calculus & Beyond Homework 2
Calculating Fourier Coefficients Advanced Physics Homework 2
Calculating fourier coefficients Calculus & Beyond Homework 3