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Fermat's Last theorem |
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| Aug28-07, 01:31 PM | #1 |
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Fermat's Last theorem
We all know of this theorem which was finally proved in the 1960's. It says that we cannot find any real integral solution for n>2 when an integer is expressed to a power of 'n' and is equal to the sum of two numbers which individually are raised to the power 'n'.
x^n=a^n+b^n Well for n=2, we are familiar with the pythagorean(3,4,5 etc.) combinations, but there is indeed is no solution when n>2...check it out. I recently ran a program to find this solution, but couldn't find for n=3,4,5... This certainly validates the theorem but how do we prove it mathematically? |
| Aug28-07, 01:34 PM | #2 |
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I thought it was proved in the '90s?
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| Aug28-07, 01:35 PM | #3 |
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Either try all infinite 'n' - might take a while (actually only need to test all the infinite number of prime n's)
or learn an awful lot of seriously complicated number theory about elliptic curves and some conjecture that I can't even spell as Andrew Wiles did. There isn't a proof understandable by mere mortals. |
| Aug28-07, 01:37 PM | #4 |
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Fermat's Last theorem
Yes, thats a mistake, it was done so in the 90's but that's apart from the point...
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| Aug28-07, 01:43 PM | #5 |
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There is a good book by Simon Singh, but since it is pretty impossible to even outline the numerical techniques to someone without grad school maths it mainly concentrates on the stories of the people involved.
It would be interesting to know what Fermat's original proof was and where he went wrong! |
| Aug29-07, 06:06 AM | #6 |
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There was no original proof. After he wrote his comment in the margin of a book, he gave completely different proofs for n= 3 and n= 4. He wouldn't have done that if he had a proof for all n.
What happened to Fermat is what happens to mathematicians all the time- he saw a way of extending result he already had and wrote that "marginal" comment. Later he realized it didn't extend as he thought. |
| Aug29-07, 06:45 AM | #7 |
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Also known as the Taniyama–Shimura conjecture. Don't even bother starting unless you already know what elliptic curves and modular functions have to do with each other. (I don't. Not a clue.)
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| Aug29-07, 09:15 AM | #8 |
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I wouldn't say it is "also known as". Yes, Wiles proved the Taniyama-Shimura conjecture. It has already been proven that Fermat's last theorem was true if and only if theTaniyama-Shimura conjecture was true.
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| Aug29-07, 10:46 PM | #9 |
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The German mathematician Frey announced that he believes that Fermat's equation, if false, will imply that the Taniyami-Shimura Conjeture to be false. This became known as the Eplison Conjecture. Soon the mathematician Kenneth Ribet actually prove this idea in detail. Wiles immediately realized that all he needs to do know if prove the Taniyami-Shimura Conjecture.
In the old days, Fermat's problem was attacked by Kummer Ideal Complex numbers. But this does not work succesfully. There is a book (I forgot the name) which teaches algebraic number theory while simultaneously working with Fermat's equation in a classical approach. |
| Aug30-07, 07:13 AM | #10 |
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| Aug30-07, 09:37 AM | #11 |
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| Aug30-07, 09:49 AM | #12 |
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It was bit of an accident that I stumbled upon Fermat's Last Theorem. I was originally coding a program to find the smallest number, which when squared, can be expressed as the sum of two different sets of individually squared numbers, which is:
65 = 1^2+8^2 = 4^2+7^2 in terms of three three numbers, you have: 325 = 1^2+18^2 = 10^2+15^2 = 6^2+17^2 in terms of four numbers, you have: 1105 = 23^2+24^2 = 4^2+33^2 = 9^2+32^2 = 12^2+31^2 This list goes on...but what I tried to do next is replace the power of n=2 with n=3 or greater integral values. What I encountered is that the program kept looping till infinity i.e. the program never terminated for the first set of two numbers cubed individually(a^3+b^n=c^n);this led me to doubt the program. I checked the program but found no errors. So I concluded that there was no solution for a power greater than 2. I incidentally also came across Fermat's last theorem.So my conclusion was indeed justified. Code:
#include <iostream.h>
#include <conio.h>
#include <math.h>
int main()
{
long n=1,i,j,flag,s,k; //initializing
long p=3; //replace 'p' to check for any other power
while(1) //loop till infinity
{
flag=0;k=pow(n,p);
for(i=1;pow(i,p)<k;i++) //looping first number
{
for(j=i+1;pow(i,p)+pow(j,p)<=k;j++) //looping second number
{
s=pow(i,p)+pow(j,p);
if(s==k){flag++;}
if(flag==2){break;} //break out of loop if found
}
if(flag==2){break;}
}
if(flag==2){cout<<n;break;} //print number if found and the program terminates
n++;
}
return 0;
}
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| Aug30-07, 10:05 AM | #13 |
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To prove all odd numbers greater than 2 are prime numbers : Mathematician: 3 is prime number, 5 is prime number, 7 is prime number, by induction, all odd numbers greater than 2 are prime numbers Physicist: 3 is prime number, 5 is prime number, 7 is prime number, 9 is experiment error, 11 is prime number,...... Engineer : 3 is prime number, 5 is prime number, 7 is prime number, 9 is prime number, 11 is prime number,...... Computer Programmer: 3 is prime number, 5 is prime number, 7 is prime number, 7 is prime number, 7 is prime number,...... Statistician: Let us try some random numbers: 17 is prime number, 23 is prime number, 11 is prime number,...... |
| Aug30-07, 10:14 AM | #14 |
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ha...Alrighty. Agreed that the program will not run for an infinite time but if there was a solution to it, the program would have given it in a relatively short period of time.Wouldn't it? So you could conjecture that the equation is unlikely to have a solution.
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| Aug30-07, 10:18 AM | #15 |
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No. You cannot say that. The behaviour for a small, finite time, is no indicator of the over all behaviour.
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| Aug30-07, 10:33 AM | #16 |
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So what exactly is the Taniyama-Shimura conjecture? |
| Aug30-07, 10:36 AM | #17 |
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