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polar vector coordinates

 
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Sep2-07, 10:56 AM   #1
 

polar vector coordinates


i dont understand the point of [itex]\hat{\theta}[/itex] if a vector is completely described by [itex] \textbf{r}=r \hat{\textbf{r}}[/itex]

btw tex is doing something weird, apparently i can't make greek letters bold
[tex]\textbf{\delta}[/tex]
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Sep2-07, 10:18 PM   #2
 
no one of you math geniuses can answer this for me?
Sep3-07, 05:43 AM   #3
 
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I don't pretend to be a math genius but perhaps none of them understands your question. What do you mean by "a vector is completely described by [itex] \textbf{r}=r \hat{\textbf{r}}[/itex]". Are you talking about a specific vector? Because that certainly does not "completely describe" a general vector. If you have a vector "completely described" by [itex] \textbf{r}=r \hat{\textbf{r}}[/itex] then you don't need [itex]\theta'[/itex].

If you have formulas for both r' and [itex]\theta'[/itex], what makes you think that the vector is "completely described" by [itex] \textbf{r}=r \hat{\textbf{r}}[/itex]
? Perhaps it would help if you stated the precise problem.
Sep3-07, 06:27 AM   #4
 
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polar vector coordinates


[tex]\hat{\textbf{r}}[/itex] depends on [tex]\theta[/tex]... It changes according to the angle. Unless you know what [tex]\theta[/tex] is you can't draw [tex]\hat{\textbf{r}}[/itex]
Sep3-07, 12:56 PM   #5
 
Quote by HallsofIvy View Post
I don't pretend to be a math genius but perhaps none of them understands your question. What do you mean by "a vector is completely described by [itex] \textbf{r}=r \hat{\textbf{r}}[/itex]". Are you talking about a specific vector? Because that certainly does not "completely describe" a general vector. If you have a vector "completely described" by [itex] \textbf{r}=r \hat{\textbf{r}}[/itex] then you don't need [itex]\theta'[/itex].

If you have formulas for both r' and [itex]\theta'[/itex], what makes you think that the vector is "completely described" by [itex] \textbf{r}=r \hat{\textbf{r}}[/itex]
? Perhaps it would help if you stated the precise problem.
does [itex]\textbf{r}[/itex] describe a general vector in cartesian coordinates? if it does then i don't see any difference between the position vector in cartesian coordinates and in polar coordinates.

in fact i don't even understand the physical meaning of a linear combination of [itex]\hat{\textbf{r}}[/itex] and [itex]\hat{\theta}[/itex]. actually that is erroneous , i have no problem visualizing the resultant of these two vectors, i would just need to connect them head to tail. what i don't understand is what i said before, what is the point of the [itex]\hat{\theta}}[/itex]

the picture represents my understanding of the the polar coordinates in terms of the cartesian coordinates where [itex]\textbf{A}[/itex] is the vector i'm trying to describe in terms of the the polar unit vectors. is it correct? and if it is correct why can't describe [itex]\textbf{A}[/itex] by just scaling the [itex]\hat{\textbf{r}}[/itex] a little and making its [itex]\theta[/itex] argument little bigger?
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