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How do I write this?

 
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Sep15-07, 02:27 PM   #1
 
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How do I write this?


I have a solution for a PDE

[tex]U(x,t)=y^2e^{-3x} + h(x)[/tex]

Where h(x) is any function such that h(0) = 1

What notation can I use for this clause on h(x)?

My guess is:
[tex]h(x)\in \{f(x)|f(0)=1\}[/tex]

Does that make sense?
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Sep15-07, 02:49 PM   #2
 
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Sure, it's a fancy-pants way of putting it.
Sep15-07, 02:53 PM   #3
 
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Quote by arildno View Post
Sure, it's a fancy-pants way of putting it.
I like doing things the fancy-pants way
Sep15-07, 02:56 PM   #4
 

How do I write this?


Well if you want to be fancy pants, you might well want to mention what sort of hypotheses are needed on h, ie there probably should be some differentiability condition.
Sep15-07, 03:31 PM   #5
 
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True; is there a symbolic way to write 'continuous'?
Sep15-07, 04:19 PM   #6
 
[tex] \text{yeah, if } f(x) \text{ is continuous on an interval } [a,b] \text{ then } f(x) \in C[a,b] [/tex]
Sep15-07, 04:33 PM   #7
 
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I am just a tiny bit concerned that your formula,
[tex]U(x,t)=y^2e^{-3x} + h(x)[/tex]
has U(x,t) on the left but a "y" and no "t" on the right!
Sep15-07, 04:41 PM   #8
 
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Quote by HallsofIvy View Post
I am just a tiny bit concerned that your formula,
[tex]U(x,t)=y^2e^{-3x} + h(x)[/tex]
has U(x,t) on the left but a "y" and no "t" on the right!
Lol woops, should be U(x,y)
Sep15-07, 05:59 PM   #9
 
off topic but does anyone know why my latex doesnt work? i tried doing it with a bunch of little [tex] and no \text but that didnt work, so i tried what i have now and just gave up and left it like that.
Sep15-07, 06:22 PM   #10
 
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Try using \textnormal

[tex]\textnormal{This is a test}[/tex]
Sep16-07, 03:19 AM   #11
 
You do not need \textnormal
Quote by axeae View Post
[tex] \text{yeah, if } f(x) \text{ is continuous on an interval } [a,b] \text{ then } f(x) \in C[a,b] [\tex]
Simply finish with "/tex", not with "\tex", between the brackets
Sep16-07, 10:22 AM   #12
 
oh wow, i guess ive been doing latex so much i forgot not everything else uses \ instead of /
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