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Eliminate parameter in parametric equation 
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#1
Sep1807, 03:49 PM

P: 23

so the question is:
eliminate the parameter in the pair of parametric equations x = h + a secθ y = k + b tanθ to find the corresponding rectangular equation. im taking an online course of calculus and i cant find an explanation of how to do this anywhere...ive been trying but it just doesnt make sense to me yet....any help? 


#2
Sep1807, 03:52 PM

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sec^2(x)tan^2(x)=1. So solve for the sec and tan, square and subtract.



#3
Sep1807, 04:16 PM

P: 23

how do i solve for sec and tan?
sorry but this calculus thing...its been a while for me 


#4
Sep1807, 04:19 PM

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Eliminate parameter in parametric equation



#5
Sep1807, 04:42 PM

P: 23

thanks, so if i do all that...then that answers my first question too?



#6
Sep1807, 04:44 PM

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You will have eliminated theta, right? Isn't that the problem?



#7
Sep1807, 04:50 PM

P: 23

i dont even know...this is so confusing. sorry to bother you with this....



#8
Sep1807, 04:52 PM

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Just try doing it. Solve for sec and tan  then square both expressions and subtract.



#9
Sep1807, 04:53 PM

P: 23

so i would get ((xh)/a)^2  ((yk)/b)^2 = 1 ?



#10
Sep1807, 04:58 PM

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Exactly. That wasn't so bad, was it?



#11
Sep1807, 04:59 PM

P: 23

haha no thanks.



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