# Eliminate parameter in parametric equation

by teffy3001
Tags: eliminate, equation, parameter, parametric
 P: 23 so the question is: eliminate the parameter in the pair of parametric equations x = h + a secθ y = k + b tanθ to find the corresponding rectangular equation. im taking an online course of calculus and i cant find an explanation of how to do this anywhere...ive been trying but it just doesnt make sense to me yet....any help?
 Sci Advisor HW Helper Thanks P: 25,228 sec^2(x)-tan^2(x)=1. So solve for the sec and tan, square and subtract.
 P: 23 how do i solve for sec and tan? sorry but this calculus thing...its been a while for me
HW Helper
Thanks
P: 25,228
Eliminate parameter in parametric equation

 Quote by teffy3001 how do i solve for sec and tan? sorry but this calculus thing...its been a while for me
Not a calc question. x=h+a*sec(t), x-h=a*sec(t), (x-h)/a=sec(t). That sort of thing. Remember?
 P: 23 thanks, so if i do all that...then that answers my first question too?
 Sci Advisor HW Helper Thanks P: 25,228 You will have eliminated theta, right? Isn't that the problem?
 P: 23 i dont even know...this is so confusing. sorry to bother you with this....
 Sci Advisor HW Helper Thanks P: 25,228 Just try doing it. Solve for sec and tan - then square both expressions and subtract.
 P: 23 so i would get ((x-h)/a)^2 - ((y-k)/b)^2 = 1 ?
 Sci Advisor HW Helper Thanks P: 25,228 Exactly. That wasn't so bad, was it?
 P: 23 haha no thanks.

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