How to Calculate Partial Pressures and Kp for Nitrogen Oxides Mixture?

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Discussion Overview

The discussion revolves around calculating the partial pressures and equilibrium constant (Kp) for a mixture of nitrogen oxides, specifically nitrogen dioxide (NO2) and dinitrogen tetroxide (N2O4), based on given density, temperature, and pressure conditions. The focus is on applying gas laws and stoichiometry to derive the necessary values.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant describes the equilibrium mixture of nitrogen oxides and sets up the problem using the given density, temperature, and pressure to calculate partial pressures and Kp.
  • Another participant proposes using the equation relating mass and moles to establish two equations for the unknowns (n1 for NO2 and n2 for N2O4) based on the total mass of the system.
  • A third participant suggests using the ideal gas law (PV=nRT) to relate the known pressure and temperature to the number of moles, emphasizing the importance of average molar mass in the calculations.
  • This participant also notes the need to account for stoichiometry in the Kp expression, indicating that the partial pressure of the nitrogen compound should be squared in the equation.
  • A later reply includes a humorous remark about the effects of inhaling NO2, which does not contribute to the technical discussion.

Areas of Agreement / Disagreement

Participants present various approaches to the problem, but there is no consensus on the specific calculations or methods to be used. Multiple competing views remain regarding the setup and interpretation of the equations involved.

Contextual Notes

Participants do not clarify certain assumptions, such as the molecular masses of the gases involved or the specific conditions under which the calculations are made. The discussion also lacks resolution on the exact values for partial pressures and Kp.

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Gaseous oxides of nitrogen rarely occur as pure substances, but as equilibrium mixtures of them. One of these equilibrium mixtures is nitrogen dioxide and dinitrogen tetroxide. If the density of such a mixture is 2.3 g/l at 74 degrees Celsius and 1.3 atm, calculate the partial pressures of the gasses and Kp for the dissociation of dinitogen tetroxide to nitrogen dioxide.
 
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Let the volume be 1L Then total mass of the system will be

[tex]n_1*M + 2n_2*M = 2.3 g[/tex]
Where
n1 : no of mol of NO2
n1 : no of mol of N2O4
M : Molecular mass of NO2

Also PV=(n1+n2)RT

So u have two unknown and two equations u can find n1 & n2 from it And Hence Kp or partial pressure
 
Using PV=nRT, since you know P and T, you can solve for the solution in the form of moles per liter. For the rest of the problem we will assume a volume of one liter (it does not matter either way since it is only a matter of proportion). Since you have the grams pertaining to this situation you essentially have the "average molar mass of this situation." That is 2.3 grams/the total number of moles (which you are to figure out).


[molar mass of the nitrogen compound (grams/moles) X N1 (number of nitrogen compound)] + [molar mass of the dinitrogen compound (grams/moles) X N2 (number of the dinitrogen compound)]

all of this divided by 2

Solve for the proportion N1/N2, that is proportional to the moles.

Notice however, that the Kp equation for the reaction pertaining to the addition of the nitrogen to form the dinitrogen should have an exponent of 2 on the pressure of the nitrogen compound; we know that according to the stochiometric equation that there are two moles of the nitrogen compound for every dinitrogen compound.:

Kp = [partial pressure of dinitrogen compound p]/[partial pressure of nitrogen compound]^2

Note also that you will need to convert moles into pressure because of the presence of an exponent (with the assumption of 1 L as the volume, volume is insignificant information in this problem).

--------------
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There's nothing quite like a lungful of NO2 in the morning. It really gives your day a kick.

:wink:
 

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