|Sep24-07, 07:47 PM||#1|
Insane AP Chem question, please help me
Is anyone here able to help me or point me in the right direction?
Iron ores often involve a mixture of oxides and contain both Fe 2+ and Fe 3+ ions. Such an ore may be analyzed for its iron content by dissolving it in an acidic solution, reducing all of the iron to Fe 2+ ions and then titrating with a standard solution of potassium permanganate until there is just a tinge of pingk color in the solution containing the iron ions. (hint: the permanganate ion is intensely purple and Mn 2+ is colorless.) After the titration was complete, permanganate would be reduced and Fe 2+ would be oxidized.
A sample of iron ore weighing 0.3500g was dissolved in acidic solution, and all of the iron was reduced. The resulting solution was titrated with a 1.621x10^-2 Molar KMnO4 Solution. The titration endpoint was reached when 41.56 mL of the KMnO4 solution was used. Determine the mass percent of iron in the iron ore sample.
What I am thinking is that I need to create two half reactions with FeO and Fe2O3 --> Fe 2+. So I go through that and I end up with half reactions of :
2H+ + FeO -> Fe2+ + H2O
2e- + 6H+ + Fe2O3 -> 2Fe2+ + 3H2O
and then combine it to form
8H+ + 2e- + FeO + Fe2O3 --> 3Fe2+ + 4H2O
From what I've learned you are supposed to be able to cancel out the electrons when you combine the two half reactions, however in this case I only have electrons on one of the half reactions and thus I have no hope of canceling them out. Am I thinking about this correctly or is there something else I should be doing?
|Sep24-07, 08:16 PM||#2|
Your thinking is on the right track, but you are only considering one of the half-reactions there.
So you have a solution of Fe+2 (aq)
When finding the half-reactions, don’t worry about the reaction which occurs to dissolve the Iron Oxide, just assume that the Iron starts out already in solution in the form of Fe+2 ions.
The half-reactions we are talking about here make up a RedOx (Reduction-Oxidation) reaction.
One half reaction will be the reduction portion ("Gain electrons, Reduction"), the other half reaction will be the oxidization portion (Loose electrons, Oxidization).
What is oxidized in the reaction?
What is reduced?
Put these two reactions together to get the complete RedOx reaction, and the electrons should/will cancel out with the proper coefficients.
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