Incline Skier


by HT3
Tags: incline, skier
HT3
HT3 is offline
#1
Oct8-07, 02:19 PM
P: 23
1. The problem statement, all variables and given/known data
A skier is gliding along at 3m/s on horizontal frictionless snow. He suddenly starts down a 10 degree incline. His speed at the bottom is 15 m/s.
a) what is the length of the incline?
b) how long does it take for him to reach the bottom?
we know:
Vo=3m/s
Vf=15m/s
t=?
x=?
a=?

2. Relevant equations
V^2=Vo^2 +2ax



3. The attempt at a solution
i need help to find what the a is...and why it is that.
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bob1182006
bob1182006 is offline
#2
Oct8-07, 02:57 PM
P: 492
the only force acting on the skier is gravity but since the skier is going down a 10 degree incline gravity is giving him some acceleration but not 100% of it's full foce.

draw the Free Body Diagram and split up gravity into it's components where the acceleration will be parallel to the incline.
HT3
HT3 is offline
#3
Oct8-07, 05:22 PM
P: 23
okay from my freebody diagram i get sin(10)=9.8/a
a=56.4
and that is wrong....if anyone could explain to me how to do it properly please...id greatly appreciate it because i have my exam very soon.

bob1182006
bob1182006 is offline
#4
Oct8-07, 05:51 PM
P: 492

Incline Skier


it should be 9.8*sin(10). the force acting parallel to the inclined plane is mgsin(theta).


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