What is the Maximum Wavelength of Light to Remove Electrons from Rubidium?

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SUMMARY

The maximum wavelength of light capable of removing electrons from rubidium is determined using the energy required to remove one mole of electrons, which is 208.4 kJ. This energy corresponds to 3.461e-19 J for a single electron. By applying the equation E = hc/lambda, where h is Planck's constant (6.626e-34 J·s) and c is the speed of light (2.9979e8 m/s), one can calculate the maximum wavelength of light necessary for this process.

PREREQUISITES
  • Understanding of photon energy calculations using E = hc/lambda
  • Familiarity with Planck's constant (h) and the speed of light (c)
  • Knowledge of energy conversion from kJ to joules
  • Basic concepts of atomic structure and electron removal
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  • Calculate the maximum wavelength for other alkali metals using their ionization energies
  • Explore the implications of photon energy on electron transitions in different elements
  • Investigate the relationship between wavelength and energy in electromagnetic radiation
  • Learn about experimental methods for measuring photon energy and electron removal
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Chemistry students, physicists, and educators interested in atomic interactions and photon energy calculations will benefit from this discussion.

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Homework Statement


It takes 208.4 kJ of energy to remove 1 mole of electrons from an atom on the surface of rubidium metal.
What is the maximum wavelength of light capable of doing this?

Homework Equations


Ephotons=hc/lambda



The Attempt at a Solution


I don't know the energy of the photon. I know h=6.626e-34, c=2.9979e8
I'm trying to find lambda but w/o the Ephoton I don't how to solve the equation.I found the energy to remove a single electron which is 3.461e-19.
 
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If you assume that the 208.4kJ was from identical wavelength photons of just the minimum energy to remove the electron, you could work out the energy per photon then use E = hc/lambda to work out the wavelength.
 
Thank You, I was using the wrong energy.
 

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