# Projection Angle?

by chitownfireman
Tags: angle, projection
 P: 3 My teacher gave me this problem today and I have tried everything I know but I still haven't found the right answer. If anyone knows how to solve it, please share. Thanks At what projection angle will the range of a projectile equal its maximum height? Hint: 2 sin θ cos θ = sin 2 θ
 Mentor P: 8,272 Presumably you've either been given a formula for the range of a projectile, or know the kinematic equations and can derive such an equation. Do the usual thing, split up into vertical and horizontal components, and solve for each separately. You need to show some work before you get any real help, and should note that solutions are not provided on these forums at all. In future, also, please post in the homework forums. Oh, and welcome to PF.
P: 16

## Projection Angle?

the angle is 76
 P: 3 Thanks mate, but I never wanted the exact answer, I just wanted a push in the right direction. You may be right, but I am currently trying to figure it out, but thanks for the input.
 P: 16 Let A be the angle and u be the velocity of projection and g ( accel due to gravity) Range (R) = u^2sin A^2/2g Max Height(H)=u^2sin2 A/g sin 2 A = 2 sin A cos A equate R and H ( since they should be equal).. u will get sin A/cos A = 4 but sin A/cos A = tan A therfore A should be 76 degrees...
P: 1,757
 Quote by saiaspire Let A be the angle and u be the velocity of projection and g ( accel due to gravity) Range (R) = u^2sin A^2/2g Max Height(H)=u^2sin2 A/g sin 2 A = 2 sin A cos A equate R and H ( since they should be equal).. u will get sin A/cos A = 4 but sin A/cos A = tan A therfore A should be 76 degrees...
you're not suppose to give out full solutions or the answer.

 Related Discussions Engineering Systems & Design 28 Special & General Relativity 27 Introductory Physics Homework 9 Introductory Physics Homework 7