How Do You Calculate the Initial Velocity of a Projectile?

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    Projectile Velocity
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SUMMARY

The initial velocity (Vo) of a projectile fired at an angle of 28.0 degrees from a height of 46.0 meters can be calculated using the equation (Vfy)^2 = (Voy)^2 + 2 * Ay * (delta Y). In this case, the vertical component of the initial velocity (Voy) is determined as 0.47Vo, and the final vertical velocity (Vfy) is 1.95 times the vertical component. The correct calculation yields an initial velocity of 37.9 m/s, although the user initially arrived at an incorrect conclusion, indicating the need for careful application of kinematic equations.

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jennypear
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projectile is fired w/an angle of 28.0degrees above the horizontal and from height 46.0m agove the ground. the projectile strikes ground w/a speed of 1.95xVo. Find Vo

I started using the eqution
(Vfy)^2=(Voy)^2+2*Ay*(delta Y)

Voy=Vosin(theta)=.47Vo
Vfy=1.954*Vosin(theta)=.92Vo

(.92Vo)^2=(.47Vo)^2+(2*-9.8*-46)
Vo=37.9

but my answer is wrong and I can't think of another way to answer the problem...Any ideas?

Thanks for your time!
 
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