- #1
jennypear
- 16
- 0
projectile is fired w/an angle of 28.0degrees above the horizontal and from height 46.0m agove the ground. the projectile strikes ground w/a speed of 1.95xVo. Find Vo
I started using the eqution
(Vfy)^2=(Voy)^2+2*Ay*(delta Y)
Voy=Vosin(theta)=.47Vo
Vfy=1.954*Vosin(theta)=.92Vo
(.92Vo)^2=(.47Vo)^2+(2*-9.8*-46)
Vo=37.9
but my answer is wrong and I can't think of another way to answer the problem...Any ideas?
Thanks for your time!
I started using the eqution
(Vfy)^2=(Voy)^2+2*Ay*(delta Y)
Voy=Vosin(theta)=.47Vo
Vfy=1.954*Vosin(theta)=.92Vo
(.92Vo)^2=(.47Vo)^2+(2*-9.8*-46)
Vo=37.9
but my answer is wrong and I can't think of another way to answer the problem...Any ideas?
Thanks for your time!