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Youngs modulus 
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#1
Oct3007, 07:20 PM

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Hi there, I am currently looking to measure the tensile strength using Young’s Modulus for steel and brass.
My results I have obtained are comparable with published values of E. My question is regarding the formulae, the one I used was: E = F/x X l/a Where a is the original cross section of the steel and brass. The cross section measured was 8. The length was 50, however it was said that it was equal to 1 because the cylinder using pie r 2 of 50 would be approximating to 8 and therefore would be to one. I don’t really have much understanding of this, could you explain it to me. Also regarding the application of steel and brass as a structural material. I have found that due to the high Young’s Modulus, steel is more desirable in structures as a high YM means it can span larger distances and is stiffer. Whereas brass is more flexible and so as a appropriate a resource than steel. Is there any other reasons for steel as the main application rather than brass? I am looking at the difference between material stiffness and component stiffness. It is my understanding that component stiffness measure is by YM only. Whereas material stiffness tests using YM and also the size and shape of the material. Is this correct and is there any other differences between the two? Lastly, I cant seem to find the YM values for wood – mahogany and parana pine. Where would I be able to find these published values and what would these values tell us when compared to actual results 


#2
Oct3007, 08:55 PM

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#3
Oct3107, 01:05 PM

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From my results i have found that wood and brass is not inherently stiff. What examples are there of using wood and brass, that by changing it's shape or distribution would make it stiffer?



#4
Oct3107, 01:28 PM

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Youngs modulus
The modulus will change inversely to the crosssectional area. So, if you change the shape in such a way that the crosssection decreases, the modulus will increase. That is to say it will become stiffer.



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Oct3107, 08:22 PM

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