## Terminal Velocity

1. The problem statement, all variables and given/known data

A sky diver of mass 83.0 kg jumps from a slow-moving aircraft and reaches a terminal speed of 46.0 m/s.
(a) What is the acceleration of the sky diver when her speed is 30.0 m/s?

2. Relevant equations
R=-bv
mg-bv=ma

3. The attempt at a solution

since R is the resistance force acting on the sky diver: R=mg
therefore I set:
83*9.8 = -b(46),
and solve for b, b = -17.683
then plug the same numbers back into mg-bv=ma to solve for the acceleration at 30m/s
(83)(9.8)-(17.683)(30)=(83)a
a = 3.41m/s^2

but this is not correct, can someone please tell me what i did wrong?

 PhysOrg.com science news on PhysOrg.com >> Hong Kong launches first electric taxis>> Morocco to harness the wind in energy hunt>> Galaxy's Ring of Fire
 Recognitions: Homework Help Science Advisor It looks fine to me. Though you usually take fluid friction proportional to v^2, not v.
 well, so how would I approach this question with v^2? I know for sure that I got the answer incorrect because I typed it into my online homework applet, it came out to be wrong.

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