|Dec4-07, 04:14 PM||#1|
1. The problem statement, all variables and given/known data
The one end of the thermocouple is placed in 45C water, the other end in oil of unknown temperature. Of the voltmeter connected to it's end I got 1.35mV. If the sensitivity of the thermocouple is 0.05mV/C, what will the difference of temperature of the liquids be?
2. Relevant equations
This is really what I'm looking for. Not sure at all what equation I would use.
3. The attempt at a solution
Would doing something like:
1.35mV / 0.05mV/C = 27C
Would 27C be the difference
Thanks for any input
|Dec7-07, 10:13 AM||#2|
I don't see what else could it be. What does your text book say?
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