Thermocouple

Puny

1. The problem statement, all variables and given/known data

The one end of the thermocouple is placed in 45C water, the other end in oil of unknown temperature. Of the voltmeter connected to it's end I got 1.35mV. If the sensitivity of the thermocouple is 0.05mV/C, what will the difference of temperature of the liquids be?


2. Relevant equations

This is really what I'm looking for. Not sure at all what equation I would use.


3. The attempt at a solution

Would doing something like:
1.35mV / 0.05mV/C = 27C
Would 27C be the difference

Thanks for any input

Shooting Star

I don't see what else could it be. What does your text book say?