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Formula for average force?

by wyclefchick
Tags: average, force, formula, solved
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wyclefchick
#1
Dec9-07, 04:07 PM
P: 9
In a ballistics test at the police department, Officer Rios fires a 6.0 g bullet at 350 m/s into a container that stops it in 1.8 ms. What is the average force that stops the bullet?

can anyone help me to do this? or just give me the formula? The teacher gave us the right answer and it's -1.2 x 10^3N
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nicksauce
#2
Dec9-07, 04:11 PM
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The average force is the change in momentum divided by the change in time.
calcisforlovers
#3
Dec9-07, 04:13 PM
P: 7
This is just an impulse-momentum theorem problem. Impulse = Change in momentum. Impulse is F*delta t (t=time of impact) and change in momentum is just final momentum - initial momentum. Good luck

wyclefchick
#4
Dec9-07, 04:29 PM
P: 9
Formula for average force?

delta p= J
and J= F(delta t)

so

delta p=6.0g(350m/s)
delta p=2100
2100/1.8=1166.6666667

is that the same thing as 1.2x10^3?
cristo
#5
Dec9-07, 04:31 PM
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P: 8,317
Quote Quote by wyclefchick View Post
delta p= J
and J= F(delta t)

so

delta p=6.0g(350m/s)
delta p=2100
2100/1.8=1166.6666667

is that the same thing as 1.2x10^3?
It would be rounded to 1.2x10^3, yes.
wyclefchick
#6
Dec9-07, 04:34 PM
P: 9
thank you so much guys!
cristo
#7
Dec9-07, 04:36 PM
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Quote Quote by wyclefchick View Post
thank you so much guys!
You're welcome (I'll speak on behalf of the people that actually helped you! )


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