Help with velocity vector and friction questions

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Homework Help Overview

The discussion revolves around two physics problems involving velocity vectors and friction. The first problem concerns calculating the minimum stopping distance for a car based on its speed and the coefficient of friction. The second problem involves determining which step a ball will hit after rolling off a stairway with a specified horizontal velocity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the use of kinematic equations and parametric reasoning to address the stopping distance and projectile motion of the ball. Questions arise about the adequacy of given information and the interpretation of variables.

Discussion Status

Some participants have provided formulas and attempted to derive expressions for the problems, while others express confusion regarding the lack of specific values and seek further clarification. The discussion reflects a mix of attempts to apply theoretical concepts and questions about the setup of the problems.

Contextual Notes

Participants note the absence of numerical values for variables in the first problem, which complicates the application of formulas. There is also mention of the parametric nature of the questions, indicating a focus on deriving expressions rather than calculating specific outcomes.

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I can't quite get an answer for these damn questions. It feels like there is information missing.

1. Show that the minimum stopping distance for a car traveling at speed v is equal to v^2 / 2*coefficient of friction*g, where the coefficient of static friction is between tires and the road and g is acceleration due to gravity.

2. A ball rolls off the top of a stairway with a horizontal velocity of magnitude 1.5m/s. The steps are 20 cm high and 20 cm wide. Which step will the ball hit first?
 
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1. Use this formula:
vf2 = v02 + 2ax
The distance is x, v0 is v and a is the car's deceleration caused by friction.

2. Let's create an axes system of X and Y, with the origin placed in the ball's inital position (top of stairs). The ball is traveling in a parabola. By analyzing the graph I attached, you can see that as soon as the ball's vertical displacement is bigger than or equal to the horizontal displacement, the ball will hit a step. (This is because the width and height of each step is equal. If this weren't the case, things would have been a bit more complicated.) So let's write the expressions for each displacement:

Δx = vt
Δy = gt2/2

Now solve this for t:

Δx = Δy
vt = gt2/2

One of the solutions is t = 0, because when the ball is first thrown it is on a step! So that's correct. The second solution is t = 2v/g. Now go back to the Δx expression and find how much the ball has managed to travel before hitting the step. For example, if the ball traveled 0.46 meters it means that it hit the 3rd step (if we don't count the step the ball was thrown from).
 

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Last edited:
Chen said:
1. Use this formula:
vf2 = v02 + 2ax
The distance is x, v0 is v and a is the car's deceleration caused by friction.

QUOTE]

I tried but I do not have any values for those variables. I don't get how I would go about doing this question.
 
You don't need values, this is a parametric question. Find a (using what you know about the friction force) and then find the expression for x.
 
i still can't get a. please give me a little more info
 
I got a=-232.4/v^2. But I don't know where to go from there
 

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