## Solving Inequalities

Hey..This is a question I am having difficulty in solving.
4x$$\angle$$2x+1$$\leq$$3x+2

First I removed the "1"from the centre. Then I tried eliminating the X's from both sides, but that did not work. Could someone help me with this?
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 Recognitions: Gold Member Homework Help Science Advisor Staff Emeritus Solve $4x<2x+1$ and $2x+1\leq 3x+2$ separately. I would express both solutions sets as intervals. Then if both inequalities must be satisfied, what would you have to do with the two solution sets you found?
 so when i solve the 1st part i get x is less than 0.5. And when i solve the 2nd part, i got X is greater than/ equal to -1 so the solution set for the 2nd part is (-infi, -1}. I'm not sure about the solution set of the 1st part..

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## Solving Inequalities

 Quote by pinkyjoshi65 so when i solve the 1st part i get x is less than 0.5. And when i solve the 2nd part, i got X is greater than/ equal to -1
Right.

 so the solution set for the 2nd part is (-infi, -1}.
Wrong. If $x\geq-1$ then the solution set is $[-1,\infty)$.

 I'm not sure about the solution set of the 1st part..
But you practically have it. You already said that $x<0.5$. How do you write down the interval containing all the numbers that are less than 0.5?