Does anyone understand this answer? proving sin(A-B)

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SUMMARY

The discussion revolves around understanding the trigonometric identity related to the expression sin(π/2 - A) in the context of a right triangle. The confusion arises from the misinterpretation of the angles in the triangle, specifically the angle in the bottom right corner, which is correctly identified as π/2 - A, not π - A. This clarification resolves the initial misunderstanding and highlights the importance of recognizing that the two non-right angles in a right triangle must sum to π/2.

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eeuler
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I had no clue how to do this and could only grasp the first basic parts but even then i couldn't get it right and in the end i had to look at the answer, which confused me even more. So i was wondering if anyone else understands this, and if so could you describe it in words please?

Homework Statement


6k4i3jt.jpg



Homework Equations


As above


The Attempt at a Solution


89jcqhs.jpg


I understand the first part, getting cos B from the graph...yet when it gets to the other part '...angle in the bottom right hand corner of the triangle is PI - A...' i don't understand how they came to that...but i was wondering, the sin (PI/2 - A) seems to be related to a trigonometric identity? If someone could explain it that would be great.
 
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eeuler said:
I had no clue how to do this and could only grasp the first basic parts but even then i couldn't get it right and in the end i had to look at the answer, which confused me even more. So i was wondering if anyone else understands this, and if so could you describe it in words please?

Homework Statement


6k4i3jt.jpg



Homework Equations


As above


The Attempt at a Solution


89jcqhs.jpg


I understand the first part, getting cos B from the graph...yet when it gets to the other part '...angle in the bottom right hand corner of the triangle is PI - A...' i don't understand how they came to that...but i was wondering, the sin (PI/2 - A) seems to be related to a trigonometric identity? If someone could explain it that would be great.
The angle in the bottom right hand corner is NOT \pi- A. The two non-right angles in a right triangle must add to \pi/2. Since the whole angle in the upper left is A, the angle in the bottom righthand corner is \pi/2- A.
 
Thank you for that, it clears some of the confusion, thanks.
 

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