Calculate Heat of Melting Ice at 10 atm - Derive Equations & Assumptions

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SUMMARY

The heat of melting ice at 1 atm and 0 degrees Celsius is +5.9176 kJ/mol, with ice density at 0.917 g/cm³ and water density at 0.9998 g/cm³. To calculate the melting point at 10 atm, the discussion emphasizes deriving equations and making necessary assumptions. The formula dp/dt=(s2-s1)/(v2-v1) is proposed for application, though its correctness is questioned. The relationship between entropy (s), enthalpy (h), and melting temperature (Tm) is also explored for expressing Δs in terms of Δh.

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The heat of melting of ice at 1 atm and 0 degree c is +5.9176kj/mol. The density of ice under these conditions is 0.917g/cm^3 and the density fo water is 0.9998g/cm^3



What will the melting point be at 10 atm? Derive necessary equations and make necessary asumptions.



DeltaH and deltaS can be easily calculated, but i was thinking that dp/dt=(s2-s1)/(v2-v1). however i don't know if the formula is correct and how to apply to this problem. Thank you.
 
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This is a good start. Is there a relationship between s, h, and Tm, so that you can express [itex]\Delta s[/itex] in terms of [itex]\Delta h[/itex]?
 

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