Quadratic function - x-intercepts?

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SUMMARY

The discussion focuses on finding the x-intercepts of the quadratic function f(x) = -2x^2 + 12x + 12. The user correctly rewrites the equation as -2(x^2 - 6x + 6) = 0 and realizes that solving for x requires using the quadratic formula or completing the square. The consensus is that the equation does not factorize easily, confirming the necessity of applying the quadratic formula for accurate results.

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Agent_J
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f(x) = -2x^2 + 12x + 12

I was able to express it in standard form and find the maximum value, but I can't seem to get the x-intercepts

I got -2x^2 + 12x + 12 = 0
-2 (x^2 - 6x + 6) = 0

does that mean I need to use the quadratic formula or did I do something wrong?
 
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There is a Homework help zone. But you have:

-2 (x^2 - 6x + 6) = 0

If a product equals 0 at least one of the bits of the product must equal 0. So either:

-2 = 0

or:

x^2 - 6x + 6 = 0

I think we can safely assume that -2 does not equal 0. So now you can solve:

x^2 - 6x + 6 = 0

By using the quadratic equation or completing the square (although it would have been just as easy to use the quadratic equation on -2x^2 + 12x + 12) I'm fairly sure this does not factorise.
 

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