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quadratic function - x-intercepts? |
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| Apr21-04, 02:19 PM | #1 |
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quadratic function - x-intercepts?
f(x) = -2x^2 + 12x + 12
I was able to express it in standard form and find the maximum value, but I can't seem to get the x-intercepts I got -2x^2 + 12x + 12 = 0 -2 (x^2 - 6x + 6) = 0 does that mean I need to use the quadratic formula or did I do something wrong? |
| Apr21-04, 02:27 PM | #2 |
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Recognitions:
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There is a Homework help zone. But you have:
-2 (x^2 - 6x + 6) = 0 If a product equals 0 at least one of the bits of the product must equal 0. So either: -2 = 0 or: x^2 - 6x + 6 = 0 I think we can safely assume that -2 does not equal 0. So now you can solve: x^2 - 6x + 6 = 0 By using the quadratic equation or completing the square (although it would have been just as easy to use the quadratic equation on -2x^2 + 12x + 12) I'm fairly sure this does not factorise. |
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