Thread Closed

quadratic function - x-intercepts?

 
Share Thread Thread Tools
Apr21-04, 02:19 PM   #1
 

quadratic function - x-intercepts?


f(x) = -2x^2 + 12x + 12

I was able to express it in standard form and find the maximum value, but I can't seem to get the x-intercepts

I got -2x^2 + 12x + 12 = 0
-2 (x^2 - 6x + 6) = 0

does that mean I need to use the quadratic formula or did I do something wrong?
PhysOrg.com
PhysOrg
mathematics news on PhysOrg.com

>> Mathematicians analyze social divisions using cell phone data
>> Can math models of gaming strategies be used to detect terrorism networks?
>> Mathematician proves there are infinitely many pairs of prime numbers less than 70 million units apart
Apr21-04, 02:27 PM   #2
 
Recognitions:
Homework Helper Homework Help
Science Advisor Science Advisor
There is a Homework help zone. But you have:

-2 (x^2 - 6x + 6) = 0

If a product equals 0 at least one of the bits of the product must equal 0. So either:

-2 = 0

or:

x^2 - 6x + 6 = 0

I think we can safely assume that -2 does not equal 0. So now you can solve:

x^2 - 6x + 6 = 0

By using the quadratic equation or completing the square (although it would have been just as easy to use the quadratic equation on -2x^2 + 12x + 12) I'm fairly sure this does not factorise.
Thread Closed
Thread Tools


Similar Threads for: quadratic function - x-intercepts?
Thread Forum Replies
x intercepts General Math 4
[SOLVED] Quadratic Function Precalculus Mathematics Homework 8
x-intercepts Calculus & Beyond Homework 3
quadratic function Introductory Physics Homework 1
Quadratic equation and Radical function!!! General Math 1