Solve for x(t), I just keep seeing 0

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Homework Help Overview

The discussion revolves around solving the differential equation \(\frac{dx}{dt} = \sqrt{2(\frac{E}{m}) -\omega^2 x^2}\), which appears to relate to concepts in mechanics, particularly in the context of energy and motion. Participants are attempting to find the function \(x(t)\) but are encountering difficulties leading to the conclusion that \(x=0\).

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants express confusion over the meaning of \(E\) and \(m\), questioning whether \(E\) represents total energy and if \(m\) is indeed mass. There are attempts to manipulate the equation but lead to a dead end with \(x=0\). Some participants suggest differentiating the equation to find a second derivative, while others emphasize the need for clarity on the definitions of the variables involved.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations of the variables and the structure of the problem. Some guidance has been offered regarding differentiation to potentially simplify the problem, but there is no consensus on the definitions or the next steps to take.

Contextual Notes

There is uncertainty regarding the definitions of \(E\) and \(m\), as they are not explicitly provided in the problem statement. This lack of information is influencing the participants' reasoning and approaches.

lampshade
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Homework Statement


[tex]\frac{dx}{dt} = \sqrt{2(\frac{E}{m}) -\omega^2 x^2}[/tex]


Homework Equations



[tex]\frac{dx}{dt} = v[/tex]

The Attempt at a Solution



I keep ending up with the statement x=0.

[tex]\frac{dx}{dt}=\sqrt{2\frac{E}{m} -\omega^2 x^2}[/tex]

Then
[tex](dx/dt)^2 =2\frac{E}{m} -\omega^2 x^2[/tex]

and 1/2 mv^2 = E

[tex](dx/dt)^2 = v^2 - 2 \omega^2 x^2[/tex]

and with dx/dt being v that makes

[tex]0=\omega^2x^2[/tex]

and then I'm sad :-(
 
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lampshade said:

Homework Statement


[tex]\frac{dx}{dt} = \sqrt{2(\frac{E}{m}) -\omega^2 x^2}[/tex]


Homework Equations



[tex]\frac{dx}{dt} = v[/tex]

The Attempt at a Solution



I keep ending up with the statement x=0.

[tex]\frac{dx}{dt}=\sqrt{2\frac{E}{m} -\omega^2 x^2}[/tex]

Then
[tex](dx/dt)^2 =2\frac{E}{m} -\omega^2 x^2[/tex]

and 1/2 mv^2 = E

[tex](dx/dt)^2 = v^2 - 2 \omega^2 x^2[/tex]

and with dx/dt being v that makes

[tex]0=\omega^2x^2[/tex]

and then I'm sad :-(

What is exactly the question you are trying to answer?

In any case, what is E here? If it's th etotal energy, it's not simply 1/2 mv^2 since there is some potential energy.
 
Just find x(t)

I left off a 2 in my work that I just noticed and that seems to have changed things a bit. I have to rework some stuff and maybe see where that ends up. As for what E is, I don't know. Nor do I technically know that m is mass, but it seems awfully like they are. They weren't explicitly defined.
 
Last edited:
lampshade said:
Just find x(t)

I left off a 2 in my work that I just noticed and that seems to have changed things a bit. I have to rework some stuff and maybe see where that ends up. As for what E is, I don't know. Nor do I technically know that m is mass, but it seems awfully like they are. They weren't explicitly defined.

Ok, then don't assume E is 1/2 mv^2

This is a simple harmonic oscillator with E = 1/2 mv^2 + 1/2 k x^2.
 
If the problem is given just as the differential equation, you don't know what E is nor do you know that m is mass, how do you possibly conclude that E= (1/2)mv2?
(And why is this a physics problem rather than a math problem?)
 
HallsofIvy said:
If the problem is given just as the differential equation, you don't know what E is nor do you know that m is mass, how do you possibly conclude that E= (1/2)mv2?
(And why is this a physics problem rather than a math problem?)

At the time I felt that it was more of a physics problem.
 
lampshade said:
At the time I felt that it was more of a physics problem.

The best way to attack th eproblem is to differentiate your equation to get the second derivative [tex]\frac{d^2x}{dt^2}[/tex] Use the initial equation to rewrite the first derivative that appears in your result in terms of x itself. Then you will have an equation relating the second derivative to the function x(t) and you will be able to solve.
 

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