## The de Broglie wavelength

The mass of an electron is 9.11*10^-31 kg. If the de Broglie wavelength for an electron in an hydrogen atom is 3.31*10^-10 m, how fast is the electron moving relative to the speed of light? The speed of light is 3.00*10^8 m/s.

here's what I did: i solved for velocity=6.626*10^-34J/(9.11*10^-31kg)(3.31*10^-10)
v=2.1974*10^-74
and i tried to gain the percent by dividing the speed of light by velocity.

where did i go wrong?

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 Mentor Your calculation is wrong. Don't just blindly do calculations. Think...does the number your calculator has spewed out actually make any sense? When it's something ridiculous like 10^-74 m/s, the answer is emphatically NO. Kind of slow for a particle, don't you think? I get v = (0.00732)c

 Quote by plstevens The mass of an electron is 9.11*10^-31 kg. If the de Broglie wavelength for an electron in an hydrogen atom is 3.31*10^-10 m, how fast is the electron moving relative to the speed of light? The speed of light is 3.00*10^8 m/s. here's what I did: i solved for velocity=6.626*10^-34J/(9.11*10^-31kg)(3.31*10^-10) v=2.1974*10^-74 and i tried to gain the percent by dividing the speed of light by velocity. where did i go wrong?

how did u calculate.... watch the exponents first......

the magnitude is 10^7 m/s...

$$\frac{6}{9\times3}\times\frac{10^{-34}}{10^{-31}\times10^{-10}}\approx\frac{2}{9}10^7 m/s$$
this suggest us that it is better to treat the electron relativistically if we want to penetrate deep in its properties...
regards
marco

## The de Broglie wavelength

thanx Dirac :)

 so hows do i get the percentage here's what i'm doing: 3.00*10^8 m/s /100 = 0.00732/x. x=2.4*10^8, but i know this isn't right so, what shall i do?
 Mentor I'm not sure what percentage you are talking about, since it's not mentioned in the original post. For the velocity of the particle, I get: $$v = 2.197 \times 10^6 \ \ \ \frac{\textrm{m}}{\textrm{s}}$$ The question asks how fast the particle is moving relative to the speed of light. Well, their ratio is $$\frac{v}{c} = \frac{2.197 \times 10^6 \ \ \ \textrm{m/s}}{3.00 \times 10^8 \ \ \ \textrm{m/s}} = 0.00732$$ So, expressed in units of the speed of light, the velocity is $$v = 0.00732c$$ The particle is moving at 0.00732 times the speed of light. Obviously, as a percentage, that's 0.732%. So I guess if you wanted to, you could say that the particle is moving at 0.732% of the speed of light. It's a completely equivalent statement though. It doesn't add any extra meaning.