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Silly question about CrossProduct 
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#1
Mar308, 01:09 PM

P: 3,016

I just forget the rule here.
I am finding angular momentum by using r x mv If I am using the determinant to evaluate r cross v, where does the mass come in? Do I just mulyiply the result of r cross v by m? Or do I distribute m to my vector v and then use those values inside the determinant? 


#2
Mar308, 02:19 PM

Sci Advisor
HW Helper
P: 4,300

It doesn't matter. m is just a number, so
r x (m v) = (m r) x v = m (r x v) 


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