# Partical Fractions

by krnhseya
Tags: fractions, partical
 P: 104 1. The problem statement, all variables and given/known data Turn this into partial fraction. k1b1/[((k1+b1*s)(k2+b2*s))-b1$$^{2}$$s$$^{2}$$] 2. Relevant equations n/a 3. The attempt at a solution original question was to find the transfer function with springs and a damper and I reduced it to this far but I cant get the partial fraction. once i get that partical fractions, i take the inverse laplace transform and get the answer.
 P: 1,755 I'm getting dizzy reading it ... $$\frac{k_1b_1}{(k_1+b_1s)(k_2+b_2s)-b_1^2s^2}$$ Yes?
 Sci Advisor HW Helper Thanks P: 26,157 $$\frac{k_1b_1}{(k_1+b_1s)(k_2+b_2s)-b_1^2s^2}$$ krnhseya, just expand the bottom line into the form $$as^2\,+\,bs\,+\,c$$, and then factor it using the good ol' (-b ±√b^2 - 4ac)/2a.
 Quote by tiny-tim $$\frac{k_1b_1}{(k_1+b_1s)(k_2+b_2s)-b_1^2s^2}$$ krnhseya, just expand the bottom line into the form $$as^2\,+\,bs\,+\,c$$, and then factor it using the good ol' (-b ±√b^2 - 4ac)/2a.
 Sci Advisor HW Helper Thanks P: 26,157 No, it doesn't … It's $$k_1k_2\,+\,(b_1k_2\,+\,b_2k_1)s\,+\,b_1(b_2\,-\,b_1)s^2$$