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partition function

 
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Apr11-08, 06:03 PM   #1
 

partition function


1. The problem statement, all variables and given/known data
If we have a system of N independent particles and the partition function for one particle is Z_1, then is the partition function for the N particle system Z=(Z_1)^N?


2. Relevant equations



3. The attempt at a solution
I'm pretty sure that this is true for a classical system, but I'm not sure if it's true for a quantum system. Does the Pauli exclusion principle spoil this somehow?
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Apr11-08, 06:14 PM   #2
 
Even without quantum considerations, you end up with over counting if the particles are identical. See Gibb's Paradox.
Apr11-08, 06:43 PM   #3
 
Right. Sorry, I meant to write
[tex]Z={1\over {N!}}(Z_1)^N[/tex]
Does that take care of over counting?
What about the quantum case?
Apr12-08, 02:36 PM   #4
 

partition function


It is not true for the quantum case. The quantum case is easier handled via grand-partition function.
Apr12-08, 04:27 PM   #5
 
So in the quantum case, if we want to use the canonical ensemble, we have to calculate the whole partition function all in one shot?
Apr13-08, 05:06 AM   #6
 
Yep. But like I said, usually, you calculate the grand-partition function (which factorises neatly into a function of single particle states).
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